postgres中的交叉表函數不返回表中的任何值

我試圖使用交叉表函數在pgadmin 4中創建數據透視表。我已經成功地創建了一個由一個Postgres手動複製代碼（見下文），以確保公正的tablefunc擴展安裝/能夠正常工作：但是postgres中的交叉表函數不返回表中的任何值

create table sales(year int, month int, qty int); 
insert into sales values(2007, 1, 1000); 
insert into sales values(2007, 2, 1500); 
insert into sales values(2007, 7, 500); 
insert into sales values(2007, 11, 1500); 
insert into sales values(2007, 12, 2000); 
insert into sales values(2008, 1, 1000); 

SELECT * FROM crosstab(
    $$ SELECT year, month, qty FROM sales ORDER BY 1 $$, 
    $$ SELECT m FROM generate_series(1,12) m $$ 
) AS (
     year int, 
     "Jan" int, 
     "Feb" int, 
     "Mar" int, 
     "Apr" int, 
     "May" int, 
     "Jun" int, 
     "Jul" int, 
     "Aug" int, 
     "Sep" int, 
     "Oct" int, 
     "Nov" int, 
     "Dec" int 
    ); 
    year | Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec 
    ------+------+------+-----+-----+-----+-----+-----+-----+-----+-----+------+------ 
    2007 | 1000 | 1500 |  |  |  |  | 500 |  |  |  | 1500 | 2000 
    2008 | 1000 |  |  |  |  |  |  |  |  |  |  |

，試圖導入我自己的數據時，表返回空值：

select * 
from medclaims2

輸出：

member date paid_amount icd9 
1 7/30/2011 43075 ICD9-1 
2 8/16/2011 24895 ICD9-2 
3 3/7/2012 18957 ICD9-4 
4 8/16/2011 37476 ICD9-5 


SELECT * FROM crosstab(
    $$ SELECT member, icd9, paid_amount FROM medclaims2 $$, 
    $$ SELECT m FROM generate_series(1,4) m $$ 
) AS (
    member varchar(25), "ICD9-1" varchar(25),"ICD9-2" varchar(25),"ICD9-4" int,"ICD9-5" varchar(25) 
);

輸出：

member ICD9-1 ICD9-2 ICD9-4 ICD9-5 
    1    
    2    
    3    
    4

任何幫助將不勝感激，謝謝！

來源

2016-12-02 JF1141

它只是一個錯字？

Paid_Amouint

與

Paid_Amount

問候拉爾夫

來源

2016-12-02 23:55:23 szeta

哎呀那只是一個錯字在我的帖子 - 謝謝！ – JF1141

postgres中的交叉表函數不返回表中的任何值

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