轉換高的數字更低格式

Question

我怎樣才能改變高號碼是這樣的：

1,000 = 1K 
1,250 = 1,2K 
10,200 = 10,2K 
102,000 = 102K 
1,200,000 = 1,2M 

或類似的東西？

這是我的設置數量：

textCell?.ll1.text = "\(String(thumb[indexPath.row].count))" 
textCell?.ll2.text = "\(String(love[indexPath.row].count))" 

Answer 1

let formatter = NSByteCountFormatter() 

就是這樣;）

例子：

let oneFormattedNumber = formatter.stringFromByteCount(1025000000000) 
let formattedList = [1_000, 1_250, 10_200, 102_000, 1_200_000].map(formatter.stringFromByteCount) 

Answer 2

可以作爲擴展添加此功能到Int：

extension Int { 
    func shortLiteralDescription() -> String { 
     var factor = 0 
     let tokens = ["","K", "M", "G","T","P"] //If you think you will need to express more, add them here 
     var value = Double(self); 
     while (value > 1000) { 
      value /= 1000 
      factor++ 
     } 
     return "\(value)\(tokens[factor])" 
    } 
} 

然後：

400200.shortLiteralDescription() //400.2K 
4000.shortLiteralDescription()  //4.0K