SQLite的（選擇）：我不明白這一點

Question

我沒有得到我需要的解決方案：

我的代碼：

select vocbox._id, vocbox.name, vocbox.native, vocbox.foreign, count(_id_vocbox) as count 
from vocbox 
left join vocable on vocable._id_vocbox=vocbox._id 
group by vocbox._id; 

...只有提供這樣的：

，但是，我想是這樣的：

，這是我的表：

我希望有人知道正確的代碼..

Answer 1

你可以試試這個查詢

select vocbox._id, vocbox.name, ln.name as native, lf.name as foreign, count(_id_vocbox) as count 
from vocbox 
left join vocable on vocable._id_vocbox=vocbox._id 
left join language as ln on ln._id = vocbox.native 
left join language as lf on lf._id = vocbox.foreign 
group by vocbox._id;