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我在下面有一些php代碼,它將數據添加到2個表中,一個稱爲「Image Table」,另一個稱爲「Image_Question」表。我遇到的問題是,當它插入到「圖像」表中時,它不會將任何數據插入到「Image_Question」表中。它不是將數據插入表中
現在我知道PHP代碼很好,因爲它曾經能夠將數據插入到兩個表中而沒有任何問題。
只有在向我的表中添加索引和外鍵之後,纔開始出現此問題。
下面是數據插入到兩個表PHP代碼:
move_uploaded_file($_FILES["fileImage"]["tmp_name"],"ImageFiles/" . $_FILES["fileImage"]["name"]);
$imagesql = "INSERT INTO Image (ImageFile) VALUES (?)";
if (!$insert = $mysqli->prepare($imagesql)) {
// Handle errors with prepare operation here
}
//Don't pass data directly to bind_param store it in a variable
$insert->bind_param("s",$img);
//Assign the variable
$img = 'ImageFiles/'.$_FILES['fileImage']['name'];
$insert->execute();
if ($insert->errno) {
// Handle query error here
}
$insert->close();
$lastID = $mysqli->insert_id;
$imagequestionsql = "INSERT INTO Image_Question (ImageId, SessionId, QuestionId) VALUES (?, ?, ?)";
if (!$insertimagequestion = $mysqli->prepare($imagequestionsql)) {
// Handle errors with prepare operation here
echo "Prepare statement err imagequestion";
}
$qnum = (int)$_POST['numimage'];
$insertimagequestion->bind_param("isi",$lastID, $sessid, $qnum);
$sessid = $_SESSION['id'] . ($_SESSION['initial_count'] > 1 ? $_SESSION['sessionCount'] : '');
$insertimagequestion->execute();
if ($insertimagequestion->errno) {
// Handle query error here
}
$insertimagequestion->close();
下面是SHOW CREATE TABLE
的映象表的輸出,Image_Question表,也是問題表作爲Image_Question表涉及到該表:
圖片表:
CREATE TABLE `Image` (
`ImageId` int(10) NOT NULL AUTO_INCREMENT,
`ImageFile` varchar(250) NOT NULL,
PRIMARY KEY (`ImageId`)
) ENGINE=InnoDB AUTO_INCREMENT=12 DEFAULT CHARSET=utf8
Image_Question表:
CREATE TABLE `Image_Question` (
`ImageQuestionId` int(10) NOT NULL AUTO_INCREMENT,
`ImageId` int(10) NOT NULL,
`SessionId` varchar(10) NOT NULL,
`QuestionId` int(5) NOT NULL,
PRIMARY KEY (`ImageQuestionId`),
KEY `FK_QuestionImage` (`ImageId`),
KEY `questionId` (`QuestionId`),
KEY `sessionId` (`SessionId`),
CONSTRAINT `FK_Image_Question` FOREIGN KEY (`SessionId`) REFERENCES `Question` (`SessionId`) ON DELETE CASCADE,
CONSTRAINT `FK_question` FOREIGN KEY (`QuestionId`) REFERENCES `Question` (`QuestionId`) ON DELETE CASCADE,
CONSTRAINT `FK_QuestionImage` FOREIGN KEY (`ImageId`) REFERENCES `Image` (`ImageId`) ON DELETE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=10 DEFAULT CHARSET=utf8
問表:
CREATE TABLE `Question` (
`SessionId` varchar(10) NOT NULL DEFAULT '',
`QuestionId` int(5) NOT NULL,
`QuestionContent` varchar(5000) NOT NULL,
`NoofAnswers` int(2) NOT NULL,
`AnswerId` int(10) NOT NULL AUTO_INCREMENT,
`ReplyId` varchar(2) NOT NULL,
`QuestionMarks` int(4) NOT NULL,
`OptionId` varchar(3) NOT NULL,
PRIMARY KEY (`SessionId`,`QuestionId`),
KEY `FK_Option_Table` (`OptionId`),
KEY `FK_IndividualQuestion` (`QuestionId`),
KEY `FK_Reply` (`ReplyId`),
KEY `FK_AnswerId` (`AnswerId`)
) ENGINE=InnoDB AUTO_INCREMENT=76 DEFAULT CHARSET=utf8
請儘量熟悉的編輯工具在本網站和正確縮進代碼爲別人需要閱讀它。我相信你的答案可以更容易回答。此外,它會很高興知道MySQL是否回饋任何錯誤消息。請記住,如果外鍵的約束不匹配,插入操作可能會被拒絕。 – hakre
如果有索引和forign鍵,當你試圖插入表'Image_Question'時,你可以發佈你得到的錯誤嗎?這可能是因爲,當向「Image_Question」表中插入數據時,這些數據必須滿足這些表中的外鍵約束。檢查兩個字段'SessionId'和'QuestionId'的值。 –