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處理將解析我的一些java文件的腳本。我正在嘗試使用replaceAll（）來擺脫一些我不需要的東西。所以它是靜態的東西很容易，但有些更難。Groovy with replaceAll with wildcards
MyWebsiteTests extends MYbaseTest {
因此，對於這一個我想刪除擴展和它後面的任何東西在該行。由於
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回答
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這將做到這一點：
line.replaceAll(/(.+)\sextends.*$/, '$1')
解析與正則表達式的源代碼似乎總是在眼淚中收場，雖然...
2
的Groovy：
assert expected == before.replaceFirst(/\s+extends\s.*/, '')
或
assert expected == before.replaceAll(/\s+extends\s.*/, '')
+0
工作。謝謝 – jrock2004
+0
@ jrock2004 - 請點擊答案左邊的數字下方的複選標記（懸停鼠標指針下的數字以顯示覆選標記），接受此答案。 –
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這對我不起作用 – jrock2004
@ jrock2004應該做...'assert'MyWebsiteTests'=='MyWebsiteTests擴展MYbaseTest {'.replaceAll（/(.+)\sextends.*$/，'$ 1'）'適用於我... –
+1 for _「用正則表達式解析源代碼似乎總是流下眼淚」_ –