如果在一個刀片插入多個記錄如何使用inserttrigger聲明

Question

我想在一個INSERT語句插入多條記錄那個時候我在我的觸發得到錯誤

誤差

Msg 512, Level 16, State 1, Procedure SetIntFlag, Line 7 Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression. The statement has been terminated.

下了扳機是

declare @act char(16)if update (first_nm) 
set @act = (select acct_no from inserted) 
update Client set Phn9_int = 1 where acct_no = @act 

如果多個列正在插入其顯示錯誤，則將其分配給一個變量。

Answer 1

假設是整個觸發：

update Client set Phn9_int = 1 where acct_no in (
    select acct_no from inserted) 

基本上，我的經驗法則是，如果你在觸發器看到任何標量，它可能相對於多行操作打破。例外是如果它使用遊標，但遊標可以避免通常。在插入，並用它

Answer 2

聲明遊標，代碼應類似於吼叫：

DECLARE @act char(16) 
DECLARE my_Cursor CURSOR FAST_FORWARD FOR SELECT acct_no FROM INSERTED; 

OPEN my_Cursor 
FETCH NEXT FROM my_Cursor into @act 

WHILE @@FETCH_STATUS = 0 
BEGIN 
    UPDATE Client SET Phn9_int = 1 where acct_no = @act 
    FETCH NEXT FROM my_Cursor into @act 
END 

CLOSE my_Cursor 
DEALLOCATE my_Cursor 

Answer 3

不要使用local_variable作爲條件WHERE子句。相反，使用簡單的JOIN條件

if update (first_nm) 
update c 
set c.Phn9_int = 1 
FROM Client c JOIN inserted i ON c.acct_no = i.acct_no