SQL Server - 減去兩個SQL查詢的結果

Question

我想在SQL Server中使用子查詢的兩個查詢的結果。

我想要實現的是計算屬於「ProductX Promotion」一部分的客戶數量，並減去屬於「ProductX Promotion」的客戶數量，並在過去60天內實際購買了ProductX。這給了我沒有購買ProductX的註冊客戶的數量，以獲得更好的營銷洞察力。

最初我只有COUNT（），因此很容易將這兩個數相減。現在需求是按客戶的狀態和Zip級別細分計數。問題出現在這裏，因爲我不能使用直接減法，我嘗試不存在，但沒有工作，我嘗試了JOIN，但仍然沒有運氣。我知道解決方案非常簡單，但我無法想象。 這裏是原來的代碼是什麼特定的列的含義的評論，

SELECT 
(SELECT COUNT (DISTINCT (c.CustomerNumber)) 
FROM Customer c 
INNER JOIN 
TransactionDetail t 
ON 
c.CustomerNumber = t.CustomerNumber 
WHERE c.ProductXPref = 1 --Indicates if Customer was part of ProductX promotion program. 
AND t.TransactionDate > DATEADD(d, -60, getdate())) 
- 
(SELECT COUNT (DISTINCT c.CustomerNumber) 
FROM Customer c 
INNER JOIN 
TransactionDetail t 
ON 
c.CustomerNumber = t.CustomerNumber 
WHERE t.ProductXIndicator = 1 --Indicates if ProductX was purchased 
AND t.TransactionDate > DATEADD(DD, -60, getdate()) 
AND c.ProductXPref = 1 --Indicates if Customer was part of ProductX promotion program. 
) AS 'Column Name' INTO #TempTable1 

這裏就是我想實現，

SELECT 
(SELECT c.Zip, c.State, COUNT (DISTINCT (c.CustomerNumber)) 
FROM Customer c 
INNER JOIN 
TransactionDetail t 
ON 
c.CustomerNumber = t.CustomerNumber 
WHERE c.ProductXPref = 1 
AND t.TransactionDate > DATEADD(d, -60, getdate()) 
GROUP BY c.Zip, c.State) 
- 
(SELECT c.Zip, c.State, COUNT (DISTINCT c.CustomerNumber) 
FROM Customer c 
INNER JOIN 
TransactionDetail t 
ON 
c.CustomerNumber = t.CustomerNumber 
WHERE t.ProductXIndicator = 1 
AND t.TransactionDate > DATEADD(DD, -60, getdate()) 
AND c.ProductXPref = 1 
GROUP BY c.Zip, c.State) AS 'Column Name' INTO #TempTable1 

這是我看到的錯誤，

消息116，級別16，狀態1，行129 子查詢未與EXISTS一起引入時，只能在選擇列表中指定一個表達式。

任何指針都會有所幫助。謝謝。

Answer 1

我覺得你在做這個要複雜得多，它需要的是 - 第一個查詢可以寫成

SELECT COUNT(DISTINCT c.CustomerNumber) 
FROM Customer c 
INNER JOIN TransactionDetail t ON c.CustomerNumber = t.CustomerNumber 
WHERE 
    c.ProductXPref = 1 --Indicates if Customer was part of ProductX promotion program. 
AND t.TransactionDate > DATEADD(d, -60, getdate())) 
AND t.ProductXIndicator <> 1 

正如你可以看到，如果你不包括在原來的這些行計算它與做另一個查詢和減法相同。

所以第二個是根本

SELECT c.Zip, c.State, COUNT(DISTINCT c.CustomerNumber) 
FROM Customer c 
INNER JOIN TransactionDetail t ON c.CustomerNumber = t.CustomerNumber 
WHERE 
    c.ProductXPref = 1 --Indicates if Customer was part of ProductX promotion program. 
AND t.TransactionDate > DATEADD(d, -60, getdate())) 
AND t.ProductXIndicator <> 1 
GROUP BY c.Zip, c.State 

Answer 2

這應該工作：

SELECT 
    c.Zip, c.State,COUNT (DISTINCT c.CustomerNumber) 
FROM 
    Customer c 
     INNER JOIN TransactionDetail t 
      ON 
       c.CustomerNumber = t.CustomerNumber AND 
       c.ProductXPref = 1 --Indicates if Customer was part of ProductX promotion program. 
       AND t.TransactionDate > DATEADD(DD, -60, getdate()) 
WHERE t.ProductXIndicator <> 1 

GROUP BY c.Zip, c.State 

Answer 3

一些驗證後的數字不匹配什麼我期望那些是，它的工作，因此我嘗試了多種不同的邏輯罰款並返回我想要的。所以在這裏張貼答案，再次感謝所有的幫助。

SELECT d.State, d.Zip, COUNT(DISTINCT(d.CustomerNumber)) AS 'Active Customers' 
    INTO #ProductDifference 
    FROM Customer c 
    INNER JOIN 
    TransactionDetail t 
    ON 
    c.CustomerNumber = t.CustomerNumber 
    WHERE d.ProductXPref = 1 
    AND t.TransactionDate > DATEADD(d, -60, getdate()) 
AND c.CustomerNumber 
NOT IN 
(SELECT DISTINCT d.[CustomerNumber] 
FROM Customer d 
    INNER JOIN 
    TransactionDetail f 
    ON 
    d.CustomerNumber = f.CustomerNumber 
WHERE f.ProductXIndicator = 1 
    AND f.TransactionDate > DATEADD(DD, -60, getdate()) 
    AND d.ProductXPref = 1) 
GROUP BY c.State, c.Zip