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這是我第一次在我的網站上使用php的觸發器。我試圖達到的條件和位置字段(位於庫存表中)更新時,觸發器將向LOG表中插入一行。更新後的DB2觸發錯誤
下面是當我chenged狀況和位置字段中顯示的錯誤:
SQL0723N An error occurred in a triggered SQL statement in trigger "DB2ADMIN.CONDITI".
Information returned for the error includes SQLCODE "-433",
SQLSTATE "22001" and message tokens "Condition changed from bad ". SQLSTATE=09000 SQLCODE=-723
這裏是我的觸發代碼,我使用數據工作室創建的觸發器,它成功了:
我已經編輯了扳機代碼和日誌表結構,但仍然會產生相同的錯誤
CREATE TRIGGER DB2ADMIN.CONDITION_LOG AFTER UPDATE OF CONDITION, LOCATION ON DB2ADMIN.INVENTORY
REFERENCING OLD AS o NEW AS n
FOR EACH ROW MODE DB2SQL NOT SECURED
INSERT INTO LOG VALUES ('',CURRENT TIMESTAMP, o.CONDITION, n.CONDITION, o.LOCATION, n.LOCATION);
我想你壞的查詢設計.. – 2013-04-08 07:07:38
最後一列的數據太長。檢查查詢過程中最後一列的長度和您嘗試插入的數據。 – Meherzad 2013-04-08 07:15:30
@Meherzad最後一列的長度爲1000個字符,應該足夠了 – 2013-04-08 07:20:47