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我實際上是編程一個簡單的服務器，它是使用tcp協議的C++中的客戶端。由於這將被集成到多人遊戲中，所以每個客戶端都必須非常快速地發送數據。tcp緩衝區中的多條消息
問題：服務器的緩衝區有時會在其中獲取多條消息。
我嘗試了各種東西，如推遲nagle的算法，但我沒有設法解決這個問題。這裏是服務器的代碼：
#ifdef __linux__
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netinet/ip.h>
#include <netinet/tcp.h>
#include <unistd.h>
#include <stdlib.h>
#include <string.h>
#include <fcntl.h>
#include <errno.h>
#include <arpa/inet.h>
#define SOCKET int
#define SOCKADDR_IN struct sockaddr_in
#endif
#ifdef _WIN32
#include <winsock2.h>
#endif
#include <cstdio>
#include <iostream>
#include <thread>
#include <vector>
#include <string>
#include "server.h"
#include "../../Logger/logger.h"
#include "../../AltisCraft.fr/Map/map.h"
#include "../../StringPlus/string_plus.h"
#include "../../AltisCraft.fr/Map/User/User.h"
void connectEvent(), receive(), sendAllUsers(string), closeConnectio(),manageMsg();
vector<SOCKET> clients;
vector<thread> clientsThreads;
vector<string> msg;
SOCKET socketId, newSocketId;
SOCKADDR_IN source;
thread connection;
char buffer[65535] = {0};
int position;
// TODO: crypt every data sendLog/receive
// TODO: whitelist ip serv
// TODO: Auth system
// TODO: timer with packet ? (double receive...)
int sendLog(SOCKET s, const char* c, int i0, int i1)
{
log("Send:");
log(c);
send(s, c, i0, i1);
}
void initializeNetwork()
{
#ifdef _WIN32
WSADATA initWin32;
WSAStartup(MAKEWORD(2, 2),&initWin32);
#endif
socketId = socket(AF_INET, SOCK_STREAM, 0);
source.sin_family = AF_INET;
source.sin_addr.s_addr = INADDR_ANY;
source.sin_port = htons(33333);
bind(socketId, (struct sockaddr*)&source, sizeof(source));
connection = thread(&connectEvent);
connection.join();
closeConnection();
}
void connectEvent()
{
int error;
while(1)
{
error = 99;
while(error != 0)
{
error = listen(socketId, 1);
}
#ifdef _WIN32
int tempo = sizeof(source);
newSocketId = accept(socketId, (struct sockaddr*)&source, &tempo);
clients.push_back(newSocketId);
#endif
#ifdef __linux__
socklen_t tempo;
newSocketId = accept(socketId, (struct sockaddr *)&source, &tempo);
clients.push_back(newSocketId);
#endif
clientsThreads.push_back(thread(&receive));
}
}
void receive()
{
int val = 1;
position = clients.size() - 1;
bool connected = 1;
while(connected)
{
buffer[65535] = {0};
if(recv(clients[position], buffer, 1515, 0) > 0)
{
string msg = buffer;
bool isEmpty = false;
log(string(inet_ntoa(source.sin_addr)) + ": " + msg);
if(startsWith(msg, "Connect "))
addUser(replace(msg, "Connect ", ""));
else if(msg == "MAJ Map")
{
log(elements);
string toSend = "MAJ Map\n" + elements;
sendLog(clients[position], toSend.c_str(), strlen(toSend.c_str()), 0);
}
else if(startsWith(msg, "MAJ User ")) /// optimize: don't sendLog pos to player who sendLog
{
msg = replace(msg, "MAJ User ", "");
if(startsWith(msg, "Pos "))
{
msg = replace(msg, "Pos ", "");
vector<string> elements = split(msg, " ");
User user = *getUserByName(elements[0] + " " + elements[1]);
user.updateView(user.getView().updatePosition(Position(convertStrToDouble(elements[2]), convertStrToDouble(elements[3]), convertStrToDouble(elements[4]))));
}
else if(startsWith(msg, "ViewAngle "))
{
msg = replace(msg, "ViewAngle ", "");
vector<string> elements = split(msg, " ");
User user = *getUserByName(elements[0] + " " + elements[1]);
user.updateView(user.getView().updateViewAngle(ViewAngle(convertStrToDouble(elements[2]), convertStrToDouble(elements[3]))));
}
}
else
sendAllUsers(string(string(inet_ntoa(source.sin_addr)) + ": " + msg).c_str());
}
else
connected = 0;
}
shutdown(clients[position], 2);
for(int i=0;i<msg.size();i++)
cout << msg[i] << endl;
#ifdef _WIN32
closesocket(clients[position]);
#endif
#ifdef __linux__
close(clients[position]);
#endif
clients.erase(clients.begin() + position);
}
void sendAllUsersWithoutOne(string msg, string name)
{
for(int j = 0; j < (int)clients.size(); j++)
{
// only linux here (MSG_DONTWAIT)
#ifdef __linux__
if(recv(clients[j], NULL, 1, MSG_PEEK | MSG_DONTWAIT) == 0)
{
clients.erase(clients.begin() + j);
continue;
}
#endif
sendLog(clients[j], msg.c_str(), strlen(msg.c_str()), 0);
}
}
void sendAllUsers(string msg)
{
for(int j = 0; j < (int)clients.size(); j++)
{
// only linux here (MSG_DONTWAIT)
#ifdef __linux__
if(recv(clients[j], NULL, 1, MSG_PEEK | MSG_DONTWAIT) == 0)
{
clients.erase(clients.begin() + j);
continue;
}
#endif
sendLog(clients[j], msg.c_str(), strlen(msg.c_str()), 0);
}
}
void closeConnection()
{
for(int i = 0; i < (int)clients.size(); i++)
{
shutdown(clients[i], 2);
#ifdef _WIN32
closesocket(clients[i]);
#endif
#ifdef __linux__
close(clients[i]);
#endif
}
#ifdef _WIN32
closesocket(socketId);
WSACleanup();
#endif
#ifdef __linux__
close(socketId);
#endif
}
void freeNetwork()
{
closeConnection();
}`
嗯......你忘了提問題了。 –
@Error - 句法懊悔我把它放在粗體中。 –
首先，如果您需要非常快速地發送/接收數據，您不應該使用TCP - 嘗試使用UDP。如果緩衝區中有多條消息，則應該嘗試從緩衝區讀取，直到它爲空 - 另一件事是，您還應該準備好緩衝區可能只包含消息的一部分，這種情況下您將無法讀取直到收到其餘的消息。您還應該考慮使用非阻塞套接字和/或微線程協程。 – olgierdh