寫這篇SQL中的Kohana查詢生成器

Question

SELECT users.* 
FROM users INNER JOIN roles_users ON users.id = roles_users.user_id 
WHERE roles_users.role_id IN (1, 2) 
GROUP BY users.id 
HAVING COUNT(*) = 2 

我來到這麼遠：

DB::select()->from('users')->join('roles_users') 
->on('users.id', '=', 'roles_users.user_id') 
->where('roles_users.role_id', 'IN', array(1, 2)) 

我可怎麼辦GROUP BY和Kohana的查詢生成器HAVING COUNT（*）？

Answer 1

你爲什麼不這樣做呢？

$query = DB::query(Database::SELECT, 
'SELECT users.* 
FROM users INNER JOIN roles_users ON users.id = roles_users.user_id 
WHERE roles_users.role_id IN (1, 2) 
GROUP BY users.id 
HAVING COUNT(*) = 2' 
); 

$query->execute(); 

例子：

$results = DB::query(Database::SELECT, 
    'SELECT * FROM 
    post_scheduled 
    WHERE 
    DATE(FROM_UNIXTIME(scheduled)) = DATE(NOW()) 
    AND 
    TIME_FORMAT(FROM_UNIXTIME(scheduled), "%H:%i") = TIME_FORMAT(NOW(), "%H:%i") 
    AND 
    published = 0' 
    )->execute()->as_array(); 

    foreach($results as $result) 
    { 
     $id = $result['id'];  
     # ... 
    } 

查詢生成器......（沒有測試）

DB::select() 
->from('users') 
->join('roles_users') 
->on('users.id', '=', 'roles_users.user_id') 
->where('roles_users.role_id', 'IN', array(1, 2)) 
->group_by('users.id') 
->having('COUNT(*)', '=', '2');