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我創建了一個控制檯項目,並將Quartz.Framework,QuartzCore.Framework添加到我的應用程序中。Quartz:構建x86_64架構時未定義的符號
但連接它給了以下錯誤
Undefined symbols for architecture x86_64:
"_CGColorCreateGenericRGB", referenced from:
GifFlippingBook::GifFlippingBookCreator::CreateGifFlippingBook(int, int, double, std::string, int, std::string, std::string, int, std::string, std::string, std::string) in main.o
"_CGDataProviderCreateWithFilename", referenced from:
GifFlippingBook::GifFlippingBookCreator::CreateGifFlippingBook(int, int, double, std::string, int, std::string, std::string, int, std::string, std::string, std::string) in main.o
"_CGImageCreateWithPNGDataProvider", referenced from:
GifFlippingBook::GifFlippingBookCreator::CreateGifFlippingBook(int, int, double, std::string, int, std::string, std::string, int, std::string, std::string, std::string) in main.o
任何想法,爲什麼時?
它沒有出現在Xcode的可用框架中,是不是嵌入到Quartz框架中? – deimus
當我將Base SDK切換到iOS時,我正在創建純粹的Mac OS X項目。爲什麼當我將它設置爲Mac OS X時,框架不顯示 – deimus