使用AJAX將SQL表格加載到HTML表格

我想使用AJAX將多個SQL查詢加載到HTML表格中。我一直在使用教程來使用AJAX將值加載到選項框中作爲我的基礎，但無法使其工作。使用AJAX將SQL表格加載到HTML表格

<script> 
$(document).ready(function($) { 
    var list_target_id = "tableDiv"; 
    var list_select_id = "year"; 
    var initial_target_html = "Fill in option boxes first"; 

    $('#'+list_target_id).html(initial_target_html); 

    $('#'+list_select_id).change(function(e) { 
    var year = $(this).val(); 
    var month = $(month).val(); 
    var companyID = $(company).val(); 

    if (year == "" && companyID == "" && month == "") { 
     $('#'+list_target_id).html(initial_target_html); 
    } else { 
     $.ajax({url: 'ajax-getvalues2.php?month='+month+'&year='+year&companyID='+companyID, 
      success: function(output) { 

       $('#'+list_target_id).html(output); 
      }, 
      error: function (xhr, ajaxOptions, thrownError) { 
      alert(xhr.status + " "+ thrownError); 
      }}); 
     } 
    }); 
}); 
</script>

Ajax的getvalues2.php：

<?php 
$connection = mysqli_connect("localhost", "Query", "Query", "database1"); 

$companyID = mysqli_real_escape_string($connection, $_GET['companyID']); 
$month = mysqli_real_escape_string($connection, $_GET['month']); 
$year = mysqli_real_escape_string($connection, $_GET['year']); 

$date = $year + "/" + $month + "/01"; 

$date1 = $date.setMonth(date.setMonth()-1); 
$date2 = $date.setMonth(date.setMonth()-2); 
$date3 = $date.setMonth(date.setMonth()-3); 
$date4 = $date.setMonth(date.setMonth()-4); 
$date5 = $date.setMonth(date.setMonth()-5); 
$date6 = $date.setMonth(date.setMonth()-6); 

echo  '<table id="myTable" class="table table-hover table-bordered">'; 

mysqli_select_db($connection, "database1"); 

$array = mysqli_query($connection, "SELECT DISTINCT buildingList.siteName, buildingList.siteId FROM buildingList INNER JOIN meterList ON buildingList.siteId = meterList.siteId WHERE buildingList.companyID = '$companyID' AND meterList.meterType = '$meterType'"); 


for (i=0, i < array.length, i++){ 
$siteId = $array[i]; 


$q2= mysqli_query($connection, "SELECT value FROM meterList WHERE siteId = '$siteId' AND meterType.meterList = '$meterType' AND date = '$date1'"); 
$q3= mysqli_query($connection, "SELECT value FROM meterList WHERE siteId = '$siteId' AND meterType.meterList = '$meterType' AND date = '$date2'"); 
$q4= mysqli_query($connection, "SELECT value FROM meterList WHERE siteId = '$siteId' AND meterType.meterList = '$meterType' AND date = '$date3'"); 
$q5= mysqli_query($connection, "SELECT value FROM meterList WHERE siteId = '$siteId' AND meterType.meterList = '$meterType' AND date = '$date4'"); 
$q6= mysqli_query($connection, "SELECT value FROM meterList WHERE siteId = '$siteId' AND meterType.meterList = '$meterType' AND date = '$date5'"); 
$q7= mysqli_query($connection, "SELECT value FROM meterList WHERE siteId = '$siteId' AND meterType.meterList = '$meterType' AND date = '$date6'"); 

echo '<td>' array[i] "</td>"; 
echo '<td contenteditable='true' type="text" onkeyup="consumption()">" "</td>"; 
echo '<td>' .$row['q2']. '</td>'; 
echo '<td></td>'; 
echo '<td>' .$row['q3']. '</td>'; 
echo '<td></td>'; 
echo '<td>' .$row['q4']. '</td>'; 
echo '<td></td>'; 
echo '<td>' .$row['q5']. '</td>'; 
echo '<td></td>'; 
echo '<td>' .$row['q6']. '</td>'; 
echo '<td></td>'; 
echo '<td>' .$row['q7']. '</td>'; 
echo '<td></td>'; 

} 

echo "</table>"; 

mysqli_free_result($result); 
mysqli_close($connection); 

?>

月應輸入到PHP文件爲「01」的一月和今年應該是在HTML文件的底部

AJAX腳本2016年輸入爲「2016」。然後將其合併爲年/月/ 01等日期。

我不完全確定我哪裏出了問題，但我可以給我一些建議。在此先感謝:)

來源

2017-04-03 TakeoGFX

究竟是什麼工作？你看到一個錯誤？數據格式不正確？您必須向我們提供線索，以瞭解哪些功能無法正常工作。 –

@SloanThrasher我嘗試了一下瀏覽器並轉至http：//localhost/ajax-getvalues2.php？month = 04＆year = 2016＆companyID = 1，但頁面只是空白，我會認爲那裏顯示的東西 – TakeoGFX

啓用錯誤reporing –

你的腳本不會編譯，所以你不會看到任何東西。例如，該行：

echo '<td>' array[i] "</td>";

應該是：

echo '<td>' . array[i] . "</td>";

他們可能是其他錯誤。打開錯誤報告對PHP錯誤的方法是：

error_reporting(E_ERROR | E_WARNING | E_PARSE | E_COMPILE_ERROR | E_STRICT);

穿上線在腳本中的第一個\ < \ PHP後吧？

來源

2017-04-03 17:19:00

使用AJAX將SQL表格加載到HTML表格

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