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我在R工作組下面的代碼來湊網頁信息的列表:追加在R裏面,列表數據幀中單列
library(rvest)
crickbuzz <- read_html(httr::GET("http://www.cricbuzz.com/cricket -match/live-scores"))
matches_dates <- crickbuzz %>%
html_nodes(".schedule-date:nth-child(1)")%>%
html_attr("timestamp")
matches_dates
[1] "1452268800000" "1452132000000" "1452247200000" "1452242400000" "1452327000000" "1452290400000" "1452310200000" "1452310200000" "1452310200000"
[10] "1452310200000" "1452324600000" "1452324600000" "1452324600000" "1452324600000" "1452324600000" "1452150000000" "1452153600000" "1452153600000"
現在我將其轉換爲正確的日期和時間格式
dates <- lapply(X = matches_date , function(timestamp_match){
(as.POSIXct(as.numeric(timestamp_match)/1000, origin="1970-01-01")) })
和現在我有以下表格日期:
dates
[[1]]
[1] "2016-01-10 07:30:00 IST"
[[2]]
[1] "2016-01-10 21:30:00 IST"
[[3]]
[1] "2016-01-09 12:00:00 IST"
[[4]]
[1] "2016-01-10 13:55:00 IST"
[[5]]
[1] "2016-01-10 10:50:00 IST"
[[6]]
[1] "2016-01-07 12:30:00 IST"
[[7]]
[1] "2016-01-07 13:30:00 IST"
[[8]]
[1] "2016-01-10 09:00:00 IST"
[[9]]
[1] "2016-01-10 09:00:00 IST"
[[10]]
[1] "2016-01-10 09:00:00 IST"
[[11]]
[1] "2016-01-10 09:00:00 IST"
[[12]]
[1] "2016-01-10 09:00:00 IST"
[[13]]
[1] "2016-01-10 13:00:00 IST"
[[14]]
[1] "2016-01-10 13:00:00 IST"
[[15]]
[1] "2016-01-10 13:00:00 IST"
[[16]]
[1] "2016-01-10 13:00:00 IST"
[[17]]
[1] "2016-01-10 03:30:00 IST"
[[18]]
[1] "2016-01-10 03:30:00 IST"
現在我附加到這個數據幀中的一個柱:
matches_info [,「日期和時間」] < - 日期
,但只有第一個日期是越來越複製整列並給予以下警告。
Warning message:
In `[<-.data.frame`(`*tmp*`, , "Date And Time", value = list(1452391200, :
provided 18 variables to replace 1 variables
如果我會做unlist(日期)它再次給我時間戳。我怎麼能誇大日期和時間?
最終,你可以做'日期< - sapply(X = matches_date,...)'而不是'lapply' – jogo
這是lapply的需求嗎? 'as.POSIXct(as.numeric(matches_date)/ 1000,origin =「1970-01-01」)'是否足夠?所有涉及的功能都是矢量化的。 – nicola