使用select sql語句篩選表數據

Question

我想使用select語句篩選表數據，我有四列，並且我還有四個文本框可以在每列中進行搜索，並且我可以在任何框中輸入值（es） ，當我在文本框中輸入值時，我想返回與我輸入的值相匹配的記錄，我該怎麼做？

ALTER PROCEDURE dbo.test_search 

    (
     @ID int, 
    @FirstName nvarchar(50), 
    @MiddleName nvarchar(50), 
    @LastName nvarchar(50) 
    ) 

AS 
    SELECT  ID, FirstName, MiddleName, LastName 
    FROM   StudentsInformation 
    WHERE (@ID IS NULL OR StudentsInformation.ID = @ID) AND 
      (@FirstName IS NULL OR StudentsInformation.FirstName = @FirstName)AND 
      (@MiddleName IS NULL OR StudentsInformation.MiddleName = @MiddleName)AND 
      (@LastName IS NULL OR StudentsInformation.LastName = @LastName) 
    RETURN 

Answer 1

編輯：

SELECT 
id 
, firstname 
, middlename 
, lastname  
FROM studentsinformation 
WHERE id = @id   
OR firstname LIKE '%' + @firstname + '%' 
    OR middlename LIKE '%' + @middlename + '%' 
    OR lastname LIKE '%' + @lastname + '%' 

可以插拔或爲，如果你想選擇對所有複選框真實記錄。

Answer 2

首先，你需要找到text-box其中搜索字符串傳遞。

根據文本框查詢可以寫在相關的column。

select * from table_name where column like '%text-box value%' 

編輯

SELECT ID,FirstName,MiddleName,LastName 
FROM StudentsInformation 
WHERE 1=1 
ID=(case when @ID <>0 AND @ID IS NOT NULL then @ID else ID end) 
and FirstName=(case when @FirstName<>'' and @FirstName IS NULL then @FirstName 
else FirstName) 
and MiddleName=(case when @MiddleName<>'' and @MiddleName IS NULL then @MiddleName 
else MiddleName) 
and LastName=(case when @LastName<>'' and @LastName IS NULL then @LastName 
else LastName) 

Answer 3

語法取決於您使用的編程語言。

但一般：

string sql="select * from tableName where" 

if((txt1.Text!="")&&(sql=="select * from tableName where") 
sql=sql+"colName like % @txt1 %" 
else 
sql=sql+" and colName like % @txt1 %" 



if((txt2.Text!="")&&(sql=="select * from tableName where") 
sql=sql+"colName like % @txt2 %" 
else 
sql=sql+" and colName like % @txt2 %" 


if((txt3.Text!="")&&(sql=="select * from tableName where") 
sql=sql+"colName like % @txt3 %" 
else 
sql=sql+" and colName like % @txt3 %" 

做這樣的。

Answer 4

我希望這將工作：

Select * from <table-name> 
where 
<Column-name1> Like 'TextBox1%' 
or 
<Column-name2> Like 'TextBox2%' 
or 
<Column-name3> Like 'TextBox2%' 
or 
<Column-name4> Like 'TextBox4%'