MySQL ORDER BY CASE不工作

Question

我想按照匹配節，細分和關鍵映射的順序來整理我的結果。現在我得到了錯誤，但是我認爲我正處在正確的軌道上來完成這個任務。我無法弄清楚如何正確設置我的情況下按照這個順序。

編輯：

我已經更新了其運作的查詢，但它仍然沒有按照正確的順序排序。

SELECT 
    list.WorkOrder, 
    list.Address, 
    locateparsed.CrossStreet, 
    list.Section, 
    list.Subdivision, 
    locateparsed.KeyMap, 
    locateparsed.City, 
    list.Score 
FROM list 
LEFT JOIN locateparsed ON locateparsed.WorkOrder = list.WorkOrder 
    WHERE locateparsed.City = "PEARLAND" 
    AND list.Completed = 0 
    AND list.Reference = 0 
    AND locateparsed.Ticket IS NOT NULL 
GROUP BY list.WorkOrder 
ORDER BY CASE 
    WHEN list.Section = 'Sec. 1' THEN 1 
    WHEN list.Subdivision = 'Shadow Ridge' THEN 2 
    WHEN locateparsed.KeyMap = '612P' THEN 3 
END 

輸出例：

WO | Address | CrossStreet | Section | Subdivision | KeyMap | City 
1 | 123 test | other | Sec. 1 | Shadow Ridge | 612P | Pearland 
2 | 111 test | other | Sec. 1 | Shadow Ridge | 612P | Pearland 
3 | 333 other | bleach | Sec. 2 | Shadow Ridge | 612P | Pearland 
4 | 334 other | bleach | Sec. 2 | Shadow Ridge | 612P | Pearland 
5 | 848 other | bleach | Sec. 2 | Shadow Ridge | 612P | Pearland 
6 | 733 blah | random | Sec. 5 | Bright Ridge | 612P | Pearland 
7 | 722 hmm | blah | Sec. 5 | Bright Ridge | 612P | Pearland 
8 | 723 hmm | blah | Sec. 5 | Bright Ridge | 612P | Pearland 
9 | 111 asdf | fdas | Sec. 30 | Other Ridge | 650P | Pearland 
10 | 123 asdf | fdas | Sec. 30 | Other Ridge | 650P | Pearland 

Answer 1

你的語法是錯誤的。它應該是：

ORDER BY CASE 
    WHEN list.Section = 'Sec. 1' THEN 1 
    WHEN list.Subdivision = 'Shadow Ridge' THEN 2 
    WHEN locateparsed.KeyMap = '612P' THEN 3 
    ELSE 4 -- anything that doesn't match above conditions comes last 
END 

這裏有一個END整個CASE表達，每個WHEN後沒有了，WHEN子句之間沒有逗號。