MySQL GROUP BY CASE錯誤

我想使用GROUP BY CASE語句量化我的查詢輸出。我在SELECT部分中的GROUP BY部分嘗試了CASE，但仍得到「錯誤代碼：1111.無效的組功能使用。」MySQL GROUP BY CASE錯誤

這裏是我的代碼（與CASE兩節）

SELECT 
case when BBsum.sum <= 9999 then '<10K' 
    when BBsum.sum <= 10999 then '<11K' 
    when BBsum.sum <= 11999 then '<12K' 
    when BBsum.sum <= 12999 then '<13K' 
    when BBsum.sum <= 13999 then '<14K' 
    when BBsum.sum <= 14999 then '<15K' 
    when BBsum.sum <= 15999 then '<16K' 
    when BBsum.sum <= 16999 then '<17K' 
    when BBsum.sum <= 17999 then '<18K' 
    when BBsum.sum <= 18999 then '<19K' 
    when BBsum.sum <= 19999 then '<20K' 
    else '20K+' end as sum, 
avg(sum(CASE when C.finance_type = 'INSTALLMENT_LOAN' then C.paid_amount end)/sum(CASE when C.finance_type = 'INSTALLMENT_LOAN' then C.initial_amount end)) as IL_RR, 
avg(sum(CASE when C.finance_type = 'PAYDAY_LOAN' then C.paid_amount end)/sum(CASE when C.finance_type = 'PAYDAY_LOAN' then C.initial_amount end)) as PDL_RR, 
avg(sum(C.paid_amount)/sum(C.initial_amount)) as RR 
FROM 
credit C 
left join (select BB.borrower_id id, sum(BB.points) sum from borrower_bonus BB 
where BB.type = 'CHARGE' 
group by bb.borrower_id) BBsum on C.borrower_id = BBsum.id 
where C.status IN ('EXPIRED', 'COMPLETED','SOLD') 
group by case when BBsum.sum <= 9999 then '<10K' 
    when BBsum.sum <= 10999 then '<11K' 
    when BBsum.sum <= 11999 then '<12K' 
    when BBsum.sum <= 12999 then '<13K' 
    when BBsum.sum <= 13999 then '<14K' 
    when BBsum.sum <= 14999 then '<15K' 
    when BBsum.sum <= 15999 then '<16K' 
    when BBsum.sum <= 16999 then '<17K' 
    when BBsum.sum <= 17999 then '<18K' 
    when BBsum.sum <= 18999 then '<19K' 
    when BBsum.sum <= 19999 then '<20K' 
    else '20K+' end 
order by sum DESC

我懷疑，我必須做一些更簡單的實現我想要的（分裂RR平均收到獎金的同夥）

來源

2017-02-23 Petya Volyak

你正在嵌套聚合函數'avg（sum（'。MySQL does not allow that – GurV

）不要使用'sum'作爲列的別名，它可能會被函數sum的代碼弄糊塗，試試類似sumOfBB。即使mysql引擎碰巧讓它通過，它的錯誤練習 – gbtimmon

您正在嵌套聚合函數，MySQL不允許。

這可能是你想要什麼：

SELECT 
case when BBsum.sum <= 9999 then '<10K' 
    when BBsum.sum <= 10999 then '<11K' 
    when BBsum.sum <= 11999 then '<12K' 
    when BBsum.sum <= 12999 then '<13K' 
    when BBsum.sum <= 13999 then '<14K' 
    when BBsum.sum <= 14999 then '<15K' 
    when BBsum.sum <= 15999 then '<16K' 
    when BBsum.sum <= 16999 then '<17K' 
    when BBsum.sum <= 17999 then '<18K' 
    when BBsum.sum <= 18999 then '<19K' 
    when BBsum.sum <= 19999 then '<20K' 
    else '20K+' end as sum, 
sum(CASE when C.finance_type = 'INSTALLMENT_LOAN' then C.paid_amount end) 
    /sum(CASE when C.finance_type = 'INSTALLMENT_LOAN' then C.initial_amount end) as IL_RR, 
sum(CASE when C.finance_type = 'PAYDAY_LOAN' then C.paid_amount end) 
    /sum(CASE when C.finance_type = 'PAYDAY_LOAN' then C.initial_amount end) as PDL_RR, 
sum(C.paid_amount)/sum(C.initial_amount) as RR 
FROM 
credit C 
left join (
    select BB.borrower_id id, sum(BB.points) sum 
    from borrower_bonus BB 
    where BB.type = 'CHARGE' 
    group by bb.borrower_id 
) BBsum on C.borrower_id = BBsum.id 
where C.status IN ('EXPIRED', 'COMPLETED','SOLD') 
group by case when BBsum.sum <= 9999 then '<10K' 
    when BBsum.sum <= 10999 then '<11K' 
    when BBsum.sum <= 11999 then '<12K' 
    when BBsum.sum <= 12999 then '<13K' 
    when BBsum.sum <= 13999 then '<14K' 
    when BBsum.sum <= 14999 then '<15K' 
    when BBsum.sum <= 15999 then '<16K' 
    when BBsum.sum <= 16999 then '<17K' 
    when BBsum.sum <= 17999 then '<18K' 
    when BBsum.sum <= 18999 then '<19K' 
    when BBsum.sum <= 19999 then '<20K' 
    else '20K+' end 
order by sum DESC

來源

2017-02-23 13:57:12 GurV

它的工作原理沒有平均值，謝謝！ –

我想你需要看您的加入你想只計算BB成員負責賬目的值，但由於左的加入，行在borrower_bonus表中沒有'CHARGE'行的貸項表將返回空值填充，然後分組到平均值中。因此，您正在計算所有獎金帳戶的平均值，而不僅是計費帳戶。內部加入將確保只有收費帳戶得到平均。

SELECT -- SELECT THE AVERAGES 
    CASE 
     WHEN BBSum.pntSum = 21 THEN '20K+' 
     ELSE CONCAT('<', BBSum.pntSum, '+') 
    END AS AccountType, 
    AVG(BBSum.RR), 
    AVG(BBSum.IL_RR), 
    AVG(BBSum.PDL_RR) 
FROM 
(
    SELECT --FIND THE RR, PDL_RR and IL_RR for each account. 
     Credit.paid_amount/Credit.initial_amount AS RR, 
     CASE WHEN Credit.finance_type = 'INSTALLMENT_LOAN' THEN RR ELSE 0 END AS IL_RR, 
     CASE WHEN Credit.finance_type = 'PAYDAY_LOAN'  THEN RR ELSE 0 END AS PDL_RR 
    FROM 
     Credit 
    WHERE 
     Credit.status IN ('EXPIRED', 'COMPLETED','SOLD') 
     AND Credit.finance_type IN ('INSTALLMENT_LOAN', 'PAYDAY_LOAN') 
) AS C 
INNER JOIN -- get all credit lines with corresponding borrowers rows. 
(
    SELECT -- Find the CHARGE account and their grouping 
     BB.borrower_id AS id 
     , CASE 
      WHEN SUM(BB.points) <= 9999 THEN 10 
      WHEN SUM(BB.points) <= 19999 THEN FLOOR(SUM(BB.points))/1000) + 1 
      ELSE 21 
     END AS pntSum 
    FROM 
     borrower_bonus AS BB 
    WHERE 
     BB.type = 'CHARGE' 
    GROUP BY 
     BB.borrower_id 
) as BBSum 
ON 
    C.Borrower_id = BBSum.id 
GROUP BY 
    BBSum.pntSum 
ORDER BY 
    BBSum.pntSum DESC

來源

2017-02-23 14:42:21 gbtimmon

這只是關於如何編寫查詢的建議。我認爲GurV正確識別的問題：

SELECT bbgroup, 
     (sum(CASE when C.finance_type = 'INSTALLMENT_LOAN' then C.paid_amount end)/
     sum(CASE when C.finance_type = 'INSTALLMENT_LOAN' then C.initial_amount end) 
     ) as IL_RR, 
     (sum(CASE when C.finance_type = 'PAYDAY_LOAN' then C.paid_amount end)/
     sum(CASE when C.finance_type = 'PAYDAY_LOAN' then C.initial_amount end) 
     ) as PDL_RR, 
     (sum(C.paid_amount)/sum(C.initial_amount)) as RR 
FROM credit C left join 
    (select BB.borrower_id, sum(BB.points) as points_sum, 
      (case when sum(BB.points) <= 9999 then '<10K' 
        when sum(BB.points) <= 10999 then '<11K' 
        when sum(BB.points) <= 11999 then '<12K' 
        when sum(BB.points) <= 12999 then '<13K' 
        when sum(BB.points) <= 13999 then '<14K' 
        when sum(BB.points) <= 14999 then '<15K' 
        when sum(BB.points) <= 15999 then '<16K' 
        when sum(BB.points) <= 16999 then '<17K' 
        when sum(BB.points) <= 17999 then '<18K' 
        when sum(BB.points) <= 18999 then '<19K' 
        when sum(BB.points) <= 19999 then '<20K' 
        else '20K+' 
       end) as bbgroup 
     from borrower_bonus BB 
     where BB.type = 'CHARGE' 
     group by bb.borrower_id 
    ) BBsum 
    on C.borrower_id = BBsum.borrower_id 
where C.status IN ('EXPIRED', 'COMPLETED','SOLD') 
group by bbgroup 
order by bbgroup DESC;

把一個複雜的case聲明在一個地方確實有助於可維護性和可讀性。我也會改變條件以符合描述：

   (case when sum(BB.points) < 10000 then '<10K' 
        when sum(BB.points) < 11000 then '<11K' 
        . . .

但是，您可能有使用999版本的特定業務規則。

來源

2017-02-23 14:42:31

MySQL GROUP BY CASE錯誤

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