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我想動態添加或連接多個sql查詢。如何動態添加多個sql查詢到paginaiton？
我正在創建一個分頁腳本，我試圖在這種情況下添加一些過濾器按鈕或鏈接，當用戶點擊鏈接時，它會將該ID添加到sql查詢中，然後顯示結果。
爲了更好地理解我的意思，我會告訴你我工作的腳本：
下面你將看到，我有三個環節;市場營銷，汽車和體育。這些鏈接代表過濾器選擇，因此當點擊「營銷」時，sql查詢將插入'category = $ ids'的市場營銷。這工作正常，除了當我想添加多個選擇，如選擇「市場營銷」和「體育」而不是'汽車'顯示。
是否有一種簡單的方法來添加多個ID到SQL連接而不是一個？
我希望這是有道理的，如果你需要任何進一步的解釋讓我知道。感謝您的幫助。
<?php
$ids=$_GET['id'];
echo $ids;
$pageN = $_GET['page'];
echo $pageN;
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>SUPERMAN</title>
<link href="../style.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script>
<script type="text/javascript" >
$(document).ready(function(){
// Filter content.
$("a.category").click(function() {
var this_id = $(this).attr('id');
$("#pagination").load('index.php?&id='+ this_id+'&page=1');
});
});
</script>
<style>
.paginate {
font-family:Arial, Helvetica, sans-serif;
padding: 3px;
margin: 3px;
}
.paginate a {
padding:2px 5px 2px 5px;
margin:2px;
border:1px solid #999;
text-decoration:none;
color: #666;
}
.paginate a:hover, .paginate a:active {
border: 1px solid #999;
color: #000;
}
.paginate span.current {
margin: 2px;
padding: 2px 5px 2px 5px;
border: 1px solid #999;
font-weight: bold;
background-color: #999;
color: #FFF;
}
.paginate span.disabled {
padding:2px 5px 2px 5px;
margin:2px;
border:1px solid #eee;
color:#DDD;
}
li{
padding:4px;
margin-bottom:3px;
background-color:#BBBECB;
list-style:none;}
ul{margin:6px;
padding:0px;}
</style>
</head>
<body>
<p>Fitler Results</p>
<br />
<a href="#" class="category" id="marketing">Marketing</a>
<a href="#" class="category" id="automotive">Automotive</a>
<a href="#" class="category" id="sports">Sports</a>
<br />
<br />
<?php
include('connect.php');
$tableName="explore";
$targetpage = "index.php";
$limit = 2;
$query = "SELECT COUNT(*) as num FROM $tableName WHERE category='$ids'";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];
$stages = 3;
$page = mysql_escape_string($_GET['page']);
if($page){
$start = ($page - 1) * $limit;
}else{
$start = 0;
}
// Get page data
//$query1 = "SELECT * FROM $tableName LIMIT $start, $limit";
$query1 = "SELECT * FROM explore WHERE category='$ids' ORDER BY category LIMIT $start, $limit";
$result = mysql_query($query1);
// Initial page num setup
if ($page == 0){$page = 1;}
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total_pages/$limit);
$LastPagem1 = $lastpage - 1;
$paginate = '';
if($lastpage > 1)
{
$paginate .= "<div class='paginate'>";
// Previous
if ($page > 1){
$paginate.= "<a href='$targetpage?page=$prev'>previous</a>";
}else{
$paginate.= "<span class='disabled'>previous</span>"; }
// Pages
if ($lastpage < 7 + ($stages * 2)) // Not enough pages to breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?&id=$ids&page=$counter'>$counter</a>";}
}
}
elseif($lastpage > 5 + ($stages * 2)) // Enough pages to hide a few?
{
// Beginning only hide later pages
if($page < 1 + ($stages * 2))
{
for ($counter = 1; $counter < 4 + ($stages * 2); $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}
// Middle hide some front and some back
elseif($lastpage - ($stages * 2) > $page && $page > ($stages * 2))
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $page - $stages; $counter <= $page + $stages; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}
// End only hide early pages
else
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $lastpage - (2 + ($stages * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
}
}
// Next
if ($page < $counter - 1){
$paginate.= "<a href='$targetpage?page=$next'>next</a>";
}else{
$paginate.= "<span class='disabled'>next</span>";
}
$paginate.= "</div>";
}
echo $total_pages.' Results';
// pagination
echo $paginate;
?>
<ul id="pagination">
<?php
while($row = mysql_fetch_array($result))
{
echo '<li>'.$row['site_name'].'</li>';
}
?>
</ul>
</body>
</html>
$ ids包含鏈接id。營銷，汽車或體育。點擊時插入到查詢中。 – DonDraper 2010-07-26 20:42:44