MySQL的聯盟不回表的名稱正確

我曾經在多個表進行搜索：MySQL的聯盟不回表的名稱正確

$query ="(SELECT *, 'product' AS type FROM products WHERE title LIKE ? OR description LIKE ? OR full_description LIKE ? OR keywords LIKE ? OR option1 LIKE ? OR option2 LIKE ? OR option3 LIKE ? OR option4 LIKE ? OR option5 LIKE ? OR option6 LIKE ? OR option7 LIKE ? OR option8 LIKE ?) 
UNION 
(SELECT *, 'article' AS type, NULL AS image1, NULL AS image2, NULL AS image3, NULL AS image4 FROM articles WHERE title LIKE ? OR description LIKE ? OR full_description LIKE ? OR keywords LIKE ? OR option1 LIKE ? OR option2 LIKE ? OR option3 LIKE ? OR option4 LIKE ? OR option5 LIKE ? OR option6 LIKE ? OR option7 LIKE ? OR option8 LIKE ?) 
UNION 
(SELECT *, 'news' AS type, NULL AS image1, NULL AS image2, NULL AS image3, NULL AS image4 FROM news WHERE title LIKE ? OR description LIKE ? OR full_description LIKE ? OR keywords LIKE ? OR option1 LIKE ? OR option2 LIKE ? OR option3 LIKE ? OR option4 LIKE ? OR option5 LIKE ? OR option6 LIKE ? OR option7 LIKE ? OR option8 LIKE ?) 
UNION 
(SELECT *, 'page' AS type, NULL AS categoryID, NULL AS categoryName, NULL AS full_description, NULL AS image, NULL AS image1, NULL AS image2, NULL AS image3, NULL AS image4, NULL AS price FROM pages WHERE title LIKE ? OR description LIKE ? OR option1 LIKE ? OR option2 LIKE ? OR option3 LIKE ? OR option4 LIKE ? OR option5 LIKE ? OR option6 LIKE ? OR option7 LIKE ? OR option8 LIKE ?) 
UNION 
(SELECT *, 'gallery_image' AS type, NULL AS categoryID, NULL AS categoryName, NULL AS full_description, NULL AS image1, NULL AS image2, NULL AS image3, NULL AS image4, NULL AS price FROM gallery_images WHERE title LIKE ? OR description LIKE ? OR option1 LIKE ? OR option2 LIKE ? OR option3 LIKE ? OR option4 LIKE ? OR option5 LIKE ? OR option6 LIKE ? OR option7 LIKE ? OR option8 LIKE ?)"; 
$selectFromTables = $this->db->prepare($query); 
$selectFromTables->execute(array("%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%", "%" . $keyword . "%")); 
$found = $selectFromTables->rowCount(); 
while($rowSearch = $selectFromTables->fetch(PDO::FETCH_ASSOC)) 
{ 
    $id = $rowSearch['id']; 
    $type = $rowSearch['type']; 
    $title = $rowSearch['title']; 
    echo $id . "->" . $type . "<br />"; 
}

爲什麼while循環返回此輸出？

23->product 
24->product 
25->product 
27->product 
28->product 
1-> 
1-> 
2-> 
4-> 
5->

但我希望這樣的輸出：

23->product 
24->product 
25->product 
27->product 
28->product 
1->article 
1->news 
2->page 
4->page 
5->page

來源

2013-07-28 Mohammad Masoudian

可能[重複]（http://stackoverflow.com/questions/15192553/pdo-fetch-returns-nothing） –

不，它不重複。 –

閱讀答案它將解決您的問題 –

這是非常有可能，你是misusing the UNION statement。

第一個SELECT語句的列名用作返回結果的列名。

我打賭你所有的表沒有相同的列數（請告訴我們所有表涉及的完整描述），使你的列別名無用。同樣，您的title列在所有表格中可能都不在同一位置。

來源

2013-07-28 21:06:38 RandomSeed

是的我的表沒有相同的列數，我通過添加NULL列來使它們的數字相同 –

太遲了:)您的*表示「所有列」，所以當您添加NULL時已經存在差異'列 - 別名'類型'列不在同一位置。嘗試明確列舉您的列（對於所有表以相同的順序）而不是'*'。 – RandomSeed

是它的正確，現在它的工作:)非常感謝你:) –

MySQL的聯盟不回表的名稱正確

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