Selenium/Python瀏覽器循環

Question

我有一個用Python編寫的基本腳本來檢查div並單擊按鈕。我使用browser.implicitly_wait自動重新加載，但是我怎樣才能讓它循環遍歷代碼而不復制它？

elem = browser.find_element_by_id('sitediv'); elem.send_keys('Red' + Keys.RETURN); 

browser.implicitly_wait(10) 

Answer 1

你可以在因特網上的python中找到關於循環的文檔。

這裏有一個例子：

• http://www.learnpython.org/en/Loops
• http://www.tutorialspoint.com/python/python_loops.htm
• http://sthurlow.com/python/lesson04/

有一個良好的閱讀！

Answer 2

這取決於你還在等什麼。

下面是一個例子，以等待與while和_is_visible功能在網頁上出現的元素，以檢查是否在頁面上存在的元素：

class DockerContainerDeployer(object): 

    self.browser = webdriver.Firefox() 

    def deploy(self) 
     # actions... 
     # wait until the docker container is deployed 
     # by checking a div that give us the status 
     while not self._is_visible("#cluster-status .deployed"): 
      # you can add an implicity wait to check it every 10s with 
      # self.browser.implicitly_wait(10) 
      pass 
     # docker container deployed 

    def _is_visible(self, locator, timeout = 2): 
     """ 
     Check if an element is visible 
     """ 

     try: 
      ui.WebDriverWait(browser, timeout).until(EC.visibility_of_element_located((By.CSS_SELECTOR, locator))) 
      return True 
     except TimeoutException: 
      return False