SQL加入當數據

匹配與我有兩個表Table 1和TableSQL加入當數據

CREATE TABLE TABLE1 (
    EMPLID VARCHAR2(11) NOT NULL, 
    COMPANY VARCHAR2(3) NOT NULL, 
    EMPL_RCD SMALLINT NOT NULL, 
    BALANCE_ID VARCHAR2(2) NOT NULL, 
    BALANCE_YEAR SMALLINT NOT NULL, 
    BALANCE_QTR SMALLINT NOT NULL, 
    BALANCE_PERIOD SMALLINT NOT NULL, 
    SPCL_BALANCE VARCHAR2(1) NOT NULL, 
    ERNCD VARCHAR2(3) NOT NULL, 
    HRS_QTD DECIMAL(13, 2) NOT NULL, 
    GRS_QTD DECIMAL(13, 2) NOT NULL, 
    HRS_YTD DECIMAL(13, 2) NOT NULL, 
    GRS_YTD DECIMAL(13, 2) NOT NULL, 
    HRS_MTD DECIMAL(13, 2) NOT NULL, 
    GRS_MTD DECIMAL(13, 2) NOT NULL); 

CREATE TABLE TABLE2(EMPLID VARCHAR2(11) NOT NULL, 
    COMPANY VARCHAR2(3) NOT NULL, 
    BALANCE_ID VARCHAR2(2) NOT NULL, 
    BALANCE_YEAR SMALLINT NOT NULL, 
    BALANCE_QTR SMALLINT NOT NULL, 
    BALANCE_PERIOD SMALLINT NOT NULL, 
    EMPL_RCD SMALLINT NOT NULL, 
    SPCL_BALANCE VARCHAR2(1) NOT NULL, 
    ERNCD VARCHAR2(3) NOT NULL, 
    HRS_YTD DECIMAL(13, 2) NOT NULL, 
    HRS_QTD DECIMAL(13, 2) NOT NULL, 
    HRS_MTD DECIMAL(13, 2) NOT NULL, 
    GRS_YTD DECIMAL(13, 2) NOT NULL, 
    GRS_QTD DECIMAL(13, 2) NOT NULL, 
    GRS_MTD DECIMAL(13, 2) NOT NULL);

我想編寫一個查詢來從表1的數據和表2從表2表1和「匹配」值返回所有行匹配值意味着，當EMPLID，ERNCD匹配時應顯示行。 EMPLID & SPCL_BALANCE之間的所有字段都是密鑰。

爲表1中的示例數據：

INSERT INTO table1 VALUES('XX','C','0','CY','2015','2','4','Y','XYZ','0','0','0','0','100001','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2015','2','5','Y','XYZ','0','0','0','0','100002','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2015','2','6','Y','XYZ','0','0','0','0','100003','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2015','3','7','Y','XYZ','0','0','0','0','100004','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2015','3','9','Y','XYZ','0','0','0','0','100005','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2015','4','10','Y','XYZ','0','0','0','0','100006','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2015','4','12','Y','XYZ','0','0','0','0','100001','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','1','1','Y','XYZ','0','0','0','0','100002','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','1','2','Y','XYZ','0','0','0','0','100003','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','1','3','Y','XYZ','0','0','0','0','100004','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','2','4','Y','XYZ','0','0','0','0','100005','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','2','6','Y','XYZ','0','0','0','0','100006','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','2','6','Y','DCP','0','100001','0','100001','0','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','2','6','Y','SAV','0','100002','0','100002','0','0'); 
INSERT INTO table1 VALUES('XX','C','0','CY','2016','2','6','Y','SUP','0','100003','0','100003','0','96949.98'); 
INSERT INTO table1 VALUES('XX','C','0','FY','2016','4','11','Y','PER','0','100004','0','100004','0','0'); 
INSERT INTO table1 VALUES('XX','C','0','FY','2016','4','11','Y','RET','0','100005','0','100005','0','0'); 
INSERT INTO table1 VALUES('XX','C','0','FY','2016','4','11','Y','SUM','0','100006','0','100006','0','0');

爲表的示例數據2

INSERT INTO table2 VALUES('XX','C','CY','2015','2','4','0','Y','XYZ','0','0','176','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2015','2','5','0','Y','XYZ','0','0','176','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2015','2','6','0','Y','XYZ','0','0','168','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2015','3','7','0','Y','XYZ','0','0','360','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2015','3','9','0','Y','XYZ','0','0','168','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2015','4','10','0','Y','XYZ','0','0','352','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2015','4','12','0','Y','XYZ','0','0','168','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2016','1','1','0','Y','XYZ','0','0','184','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2016','1','2','0','Y','XYZ','0','0','168','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2016','1','3','0','Y','XYZ','0','0','168','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2016','2','4','0','Y','XYZ','0','0','352','0','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2016','2','5','0','Y','DCP','0','0','0','100001','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2016','2','5','0','Y','SAV','0','0','0','100002','0','0') 
INSERT INTO table2 VALUES('XX','C','CY','2016','2','5','0','Y','SUP','0','0','0','100003','0','0') 
INSERT INTO table2 VALUES('XX','C','FY','2016','4','10','0','Y','PER','0','0','0','100004','0','0') 
INSERT INTO table2 VALUES('XX','C','FY','2016','4','10','0','Y','RET','0','0','0','100005','0','0')

我想寫入其顯示從表1的所有18行每當EMPLID和ERNCD相匹配的查詢，而不論其他鍵的匹配與否。

輸出採樣

t1.emplid t2.emplid t1.company t2.compnay t1.empl_rcd t2.empl_rcd t1.balance_id t2.balance_id t1.balance_year t2.balance_year t1.balance_qtr t2.balance_qtr t1.balance_period t2.balance_period t1.erncd t2.erncd 
10011024 10011024 UCS UCS 0 0 CY CY 2015 2015 2 2 4 4 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2015 2015 2 2 5 5 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2015 2015 2 2 6 6 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2015 2015 3 3 7 7 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2015 2015 3 3 9 9 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2015 2015 4 4 10 10 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2015 2015 4 4 12 12 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2016 2016 1 1 1 1 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2016 2016 1 1 2 2 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2016 2016 1 1 3 3 ACA ACA 
10011024 10011024 UCS UCS 0 0 CY CY 2016 2016 2 2 4 4 ACA ACA 
10011024 NULL UCS NULL 0 NULL CY NULL 2016 NULL 2 NULL 6 NULL ACA NULL 
10011024 10011024 UCS UCS 0 0 CY CY 2016 2016 2 2 6 5 DCP DCP 
10011024 10011024 UCS UCS 0 0 CY CY 2016 2016 2 2 6 5 SAV SAV 
10011024 10011024 UCS UCS 0 0 CY CY 2016 2016 2 2 6 5 SUP SUP 
10011024 10011024 UCS UCS 0 0 FY FY 2016 2016 4 4 11 10 PER PER 
10011024 10011024 UCS UCS 0 0 FY FY 2016 2016 4 4 11 10 RET RET 
10011024 NULL UCS NULL 0 NULL CY NULL 2016 NULL 4 NULL 11 NULL SUM NULL

我希望這有助於。我目前使用下面的SQL，但沒有得到所有行：

FROM 
     (
     select EBCS1.EMPLID ,EBCS1.COMPANY ,EBCS1.BALANCE_ID ,EBCS1.BALANCE_YEAR ,EBCS1.BALANCE_QTR , 
    EBCS1.BALANCE_PERIOD ,EBCS1.EMPL_RCD ,EBCS1.SPCL_BALANCE ,EBCS1.ERNCD ,EBCS1.HRS_YTD ,EBCS1.HRS_QTD ,EBCS1.HRS_MTD , 
    EBCS1.GRS_YTD ,EBCS1.GRS_QTD ,EBCS1.GRS_MTD 
      row_number() over (partition by EBCS1.EMPLID order by case when EBCS1.EMPLID is not null then 0 else 1 end asc, EBCS1.ERNCD) rn 
     from table1 EBCS1 left join 
     (select distinct EMPLID,EMPL_RCD, COMPANY, BALANCE_ID,BALANCE_YEAR,BALANCE_QTR,BALANCE_PERIOD,ERNCD,SPCL_BALANCE from table2) EBPS1 on 
     EBCS1.EMPLID=EBPS1.EMPLID AND EBCS1.BALANCE_ID=EBPS1.BALANCE_ID and EBCS1.COMPANY=EBPS1.COMPANY AND EBCS1.ERNCD=EBPS1.ERNCD and EBCS1.BALANCE_PERIOD = EBPS1.BALANCE_PERIOD 
    AND EBCS1.BALANCE_QTR = EBPS1.BALANCE_QTR AND EBCS1.EMPL_RCD = EBPS1.EMPL_RCD AND EBCS1.BALANCE_YEAR = EBPS1.BALANCE_YEAR 
    AND EBCS1.SPCL_BALANCE =EBPS1.SPCL_BALANCE ) EBCS 
     LEFT OUTER JOIN 
     (
     select EBPS1.EMPLID ,EBPS1.COMPANY ,EBPS1.BALANCE_ID ,EBPS1.BALANCE_YEAR ,EBPS1.BALANCE_QTR , 
    EBPS1.BALANCE_PERIOD ,EBPS1.EMPL_RCD ,EBPS1.SPCL_BALANCE ,EBPS1.ERNCD ,EBPS1.HRS_YTD ,EBPS1.HRS_QTD ,EBPS1.HRS_MTD , 
    EBPS1.GRS_YTD ,EBPS1.GRS_QTD ,EBPS1.GRS_MTD, 
      row_number() over (partition by EBPS1.EMPLID order by case when EBPS1.EMPLID is not null then 0 else 1 end asc, EBPS1.ERNCD) rn 
     from table2 EBPS1 left join (select distinct EMPLID,EMPL_RCD,COMPANY,BALANCE_ID,BALANCE_YEAR,BALANCE_PERIOD,ERNCD,SPCL_BALANCE,BALANCE_QTR 
     from table1) EBCS1 ON 
     EBCS1.EMPLID=EBPS1.EMPLID AND EBCS1.BALANCE_ID=EBPS1.BALANCE_ID and EBCS1.COMPANY=EBPS1.COMPANY AND EBCS1.ERNCD=EBPS1.ERNCD and EBCS1.BALANCE_PERIOD = EBPS1.BALANCE_PERIOD 
    AND EBCS1.BALANCE_QTR = EBPS1.BALANCE_QTR AND EBCS1.EMPL_RCD = EBPS1.EMPL_RCD AND EBCS1.BALANCE_YEAR = EBPS1.BALANCE_YEAR AND EBCS1.SPCL_BALANCE =EBPS1.SPCL_BALANCE ) EBPS 
     ON (EBPS.EMPLID=EBCS.EMPLID AND EBPS.COMPANY=EBCS.COMPANY AND EBCS.rn=EBPS.rn)

輸出使用下面的查詢：

XX1 CY CY 2 2 1 1 ACA ACA 
XX1 CY CY 3 3 1 1 ACA ACA 
XX1 CY CY 4 4 2 2 ACA ACA 
XX1 CY  6 0 2 0 ACA 
XX1 CY  6 0 2 0 DCP 
XX1 CY  6 0 2 0 SAV 
XX1 CY  6 0 2 0 SUP 
XX1 FY  11 0 4 0 SAF

預期輸出：

XX1 CY CY 2 2 1 1 ACA ACA 
XX1 CY CY 3 3 1 1 ACA ACA 
XX1 CY CY 4 4 2 2 ACA ACA 
XX1 CY NULL 6 0 2 0 ACA NULL 
XX1 CY CY 6 2 2 5 DCP DCP 
XX1 CY CY 6 2 2 5 SAV SAV 
XX1 CY CY 6 2 2 5 SUP SUP 
XX1 FY FY 11 4 10 10 SAF SAF

來源

2016-11-28 R Prasad

你似乎知道答案只是做表1 t1左t連接t2上的表2 t2.EMPLID = t2.EMPLID和t1.ERNCD = t2.ERNCD –

@EvanSteinbrenner這個問題是這個[原始問題]（http： //stackoverflow.com/questions/40038840/sql-join-with-unique-rows/40041348?noredirect=1#comment68922624_40041348）。「正常」連接應該在每個表的前8個字段中。所以EMPLID和ERNCD上的一個簡單的「左連接」會產生很多重複。 – Insac

我花更多的時間來糾正測試數據，而不是專注於您的問題:-)示例輸出不會引用您發佈的示例數據。我應該如何使用該示例輸出來驗證我的提議？ – Insac

唯一的想法，來到我的頭腦是這樣的：

select t1.emplid,t1.balance_id,t2.balance_id,t1.balance_period,t2.balance_period,t1.balance_qtr,t2.balance_qtr, t1.erncd,t2.erncd 
    from table1 t1 join table2 t2 
     on t1.emplid=t2.emplid 
    and t1.company=t2.company 
    and t1.empl_rcd=t2.empl_rcd 
    and t1.balance_id=t2.balance_id 
    and t1.balance_year=t2.balance_year 
    and t1.balance_qtr=t2.balance_qtr 
    and t1.balance_period=t2.balance_period 
    and t1.spcl_balance=t2.spcl_balance 
    and t1.erncd=t2.erncd 
    union all 
    select t1.emplid, 
     t1.balance_id, null balance_id, 
     t1.balance_period, null balance_period, 
     t1.balance_qtr, null balance_qtr, 
     t1.erncd, null erncd 
    from table1 t1 
     left join (select * from table2 t3 
        where not exists 
          (select 1 from table1 t4 
          where t3.emplid=t4.emplid 
           and t3.company=t4.company 
           and t3.empl_rcd=t4.empl_rcd 
           and t3.balance_id=t4.balance_id 
           and t3.balance_year=t4.balance_year 
           and t3.balance_qtr=t4.balance_qtr 
           and t3.balance_period=t4.balance_period 
           and t3.spcl_balance=t4.spcl_balance 
         ) 
        ) t3 
       on t1.emplid=t3.emplid 
       and t1.erncd=t3.erncd 
    where not exists 
    (select 1 from table2 t2 
     where t1.emplid=t2.emplid 
      and t1.company=t2.company 
      and t1.empl_rcd=t2.empl_rcd 
      and t1.balance_id=t2.balance_id 
      and t1.balance_year=t2.balance_year 
      and t1.balance_qtr=t2.balance_qtr 
      and t1.balance_period=t2.balance_period 
      and t1.spcl_balance=t2.spcl_balance 
    );

在查詢的第一部分，我將返回所有完全匹配的行。在第二個中，我返回了與table2連接的table1的所有行，使用相同的emplid和erncd（但只在不匹配的記錄上）。

如果這不符合您的要求，可否請您在示例中添加table2行和完整的預期結果？

對於我來說，如果使用您的數據，第二個聯合會返回重複或不重複，我不清楚。

來源

2016-11-28 21:08:25 Insac

添加了所需的信息，請檢查 –

以前的代碼似乎不完整。你能檢查嗎？ –

刪除了最後一個「和」 – Insac

SQL加入當數據

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