YaLinqo - 獲取包含等於運算符的where子句的正確結果

Question

我試圖用類似SQL的語法查詢數組，並且我正在瞭解YaLinqo。

我設法讓它適用於具有上級或下級操作符的where子句，但我不能讓它與equals操作符一起工作。

我在做什麼錯？

下面的例子：

require_once __DIR__ . '/vendor/autoload.php'; 

use \YaLinqo\Enumerable; 

$users = [ 
    [ 
     'UserId' => '1', 
     'username' => 'joe', 
     'password' => 'joepw', 
     'mail' => 'joe@mail.com' 
    ], 
    [ 
     'UserId' => '2', 
     'username' => 'nancy', 
     'password' => 'nancypw', 
     'mail' => 'nancy@mail.com' 
    ], 
    [ 
     'UserId' => '3', 
     'username' => 'alice', 
     'password' => 'alicepw', 
     'mail' => 'alice@mail.com' 
    ] 
]; 

$working = \YaLinqo\Enumerable::from($users) 
    ->where('$users ==> $users["UserId"] > 2') 
    ->toArray(); 

$notWorking = \YaLinqo\Enumerable::from($users) 
    ->where('$users ==> $users["UserId"] = 2') 
    ->toArray(); 

$workingAndUgly = \YaLinqo\Enumerable::from($users) 
    ->where('$users ==> $users["UserId"] > 1') 
    ->where('$users ==> $users["UserId"] < 3') 
    ->toArray(); 

$notWorkingEither = \YaLinqo\Enumerable::from($users) 
    ->where('$users ==> $users["username"] = "nancy"') 
    ->toArray(); 

var_dump($working, $notWorking, $workingAndUgly, $notWorkingEither); 

Answer 1

我發現，使用的==代替=作品：

// previously $notWorking 
$nowWorking = \YaLinqo\Enumerable::from($users) 
    ->where('$users ==> $users["UserId"] == 2') 
    ->toArray(); 

// previously $notWorkingEither 
$nowWorkingAlso = \YaLinqo\Enumerable::from($users) 
->where('$users ==> $users["username"] == "nancy"') 
->toArray();