如何編寫這個（詳細）Golang代碼更有效率/緊湊？

Question

我該如何寫這個塊更緊湊？我認爲寫很多簡單的代碼是很多的。

// GetSegments Retrieve segments near given coordinate. 
func GetSegments(w http.ResponseWriter, r *http.Request) { 
    near := r.FormValue("near") 
    givenCoordinate := strings.Split(near, ",") 

    lat, _ := strconv.ParseFloat(givenCoordinate[0], 32) 
    lon, _ := strconv.ParseFloat(givenCoordinate[1], 32) 

    lat32 := float32(lat) 
    lon32 := float32(lon) 

    coord := Coordinate{ 
     Latitude: lat32, 
     Longitude: lon32} 

    fmt.Println(coord) 
} 

的代碼塊是通過Web API調用： http://localhost:8080/segments?near=14.52872,52.21244

我真的很喜歡圍棋，但這是，如果我使用它的權利，我想知道的事情之一..

Answer 1

最重要的是你編寫的代碼能夠產生正確的結果和有用的錯誤信息。檢查錯誤。例如，

type Coordinate struct { 
    Latitude float32 
    Longitude float32 
} 

// GetSegments Retrieve segments near given coordinate. 
// http://localhost:8080/segments?near=14.52872,52.21244 
func GetSegments(w http.ResponseWriter, r *http.Request) (Coordinate, error) { 
    const fnc = "GetSegments" 
    near := r.FormValue("near") 
    if len(near) == 0 { 
     return Coordinate{}, fmt.Errorf("%s: near coordinates missing", fnc) 
    } 
    latlon := strings.Split(near, ",") 
    if len(latlon) != 2 { 
     return Coordinate{}, fmt.Errorf("%s: near coordinates error: %s", fnc, near) 
    } 
    lat, err := strconv.ParseFloat(latlon[0], 32) 
    if err != nil { 
     return Coordinate{}, fmt.Errorf("%s: near latitude: %s: %s", fnc, latlon[0], err) 
    } 
    lon, err := strconv.ParseFloat(latlon[1], 32) 
    if err != nil { 
     return Coordinate{}, fmt.Errorf("%s: near longitude: %s: %s", fnc, latlon[1], err) 
    } 
    coord := Coordinate{ 
     Latitude: float32(lat), 
     Longitude: float32(lon), 
    } 
    fmt.Println(coord) 
    return coord, nil 
}