簡單數組賦值

Question

我只是試圖讓填充與對象的數組的功能，但什麼是錯的：

row1 = [] 

class Tile 
    def initialize(type) 
     @type = type 
    end 
end 

def FillRow1 

    [1..10].each { 
     random = rand(1..3) 
     if random == 1 row1.(Tile.new("land") end 
     else if random == 2 row1.(Tile.new("Water") end 
     else ifrandom == 3 row1.(Tile.new("empty") end 
    } 
    row1 
end 

Answer 1

你的語法是錯誤的

[1..10].each { 
     random = rand(1..3) 
     if random == 1 then row1.push(Tile.new("land")) end 
     else if random == 2 then row1.push(Tile.new("Water")) end 
     else ifrandom == 3 then row1.push(Tile.new("empty") end 
    } 

這會工作。

但一個更清潔的解決方案可能是：

types = ["Land","Water","Empty"] 
10.times{ row1 << Tile.new(types[rand(0..2)]) } 

Answer 2

你的第二否則，如果是錯誤的，必須有隨機的，如果之間的空間。

Answer 3

a= ["land", "water", "empty"] 
data= (1..10).map{ a[rand(3)] } 
p data 

Answer 4

甲一個行選項：

10.times.map{ Tile.new(["land","water","empty"][rand(3)]) } 

Answer 5

最近紅寶石（> = 1.9.3）的版本來與方法#sample。它是Array的一部分。你甚至可以用它從數組中獲得隨機元素，甚至不需要知道甚至有多大的數組。

class Tile 
    TILE_TYPES = %w(land water empty) 

    def initialize(type) 
     @type = type 
    end 

    def to_s 
     "Tile of type: #{@type}" 
    end 
end 

# Generate 10 tiles 
rows = (1..10).map do 
    Tile.new Tile::TILE_TYPES.sample 
end 

puts rows 
#=> Tile of type: empty 
# Tile of type: land 
# ... 

# If you want to pick more then 1 random element you can also do 
puts Tile::TILE_TYPES.sample(3) 

Answer 6

class Tile 
    def initialize(type) 
    @type = type 
    end 
end 

types = %w(land water empty) 

row = Array.new(10){ Tile.new(types.sample) }