我能想到的最好的解釋是:我試圖給每個機器人一個唯一的ID。然後,當我運行程序時,我只需要給機器人一個名稱和ID。狀態是爲我生成的。以遞增值插入
但是,由於找不到正確的方法來做到這一點,我正在達到總阻礙。我已經嘗試過對行進行計數並將其放入臨時文件中。這是行不通的。每次運行它時都會創建一個新行。所以,我應該總是得到一個新的身份證。但我可能做錯了。
我得到這個錯誤:
Error(23,44): PL/SQL: ORA-00984: column not allowed here
下面是該過程:
CREATE OR replace PROCEDURE Checkbot
(nameinput IN VARCHAR2)
IS
partfound NUMBER(4);
foundall BOOLEAN;
tempid NUMBER;
BEGIN
--Where I am having issues:
SELECT Count(*)
INTO tempid
FROM robotinventory;
INSERT INTO robotinventory VALUES (tempid, nameinput, NULL);
foundall := TRUE;
FOR i IN 1..8 LOOP
partfound := 0;
SELECT Max(prtserial)
INTO partfound
FROM partinventory
WHERE parttypeid = i;
IF partfound > 0 THEN
DELETE FROM partinventory
WHERE prtserial = partfound;
INSERT INTO robotprt VALUES (tempid, idinput, i);
ELSE
foundall := FALSE;
END IF;
END LOOP;
IF foundall THEN
UPDATE robotinventory
SET status = 'ready for assembly'
WHERE robotid = tempid;
ELSE
UPDATE robotinventory
SET status = 'waiting on parts'
WHERE robotid = tempid;
END IF;
END;/
機器人庫存表:
CREATE TABLE RobotInventory
(RobotID Number(4) PRIMARY KEY,
RobotName VARCHAR2(24),
Status VARCHAR2(64));
我的代碼以前的版本,拿出我做了什麼在我的錯誤,我的目標是用一個自動遞增的數字替換idInput:
create or replace procedure checkbot
(idInput in number, nameInput in varchar2)
is
partFound number(4);
foundAll boolean;
begin
insert into robotInventory values (idInput, nameInput, null);
foundAll := true;
for i in 1..8 loop
partFound := 0;
select max(prtSerial)
into partFound
from partInventory
where ParttypeID = i;
if partFound > 0 then
delete from partInventory
where prtSerial = partFound;
insert into robotPrt values (partFound, idInput, i);
else
foundAll := false;
end if;
end loop;
if foundAll then
update robotInventory
set status = 'ready for assembly'
where robotID = idInput;
else
update robotInventory
set status = 'waiting on parts'
where robotID = idInput;
end if;
END;
/
工作的人誰的代碼是好奇:http://pastebin.com/L5WBr4Br – Kevin