比較C＃中的兩個列表ASP.NET MVC LINQ實體框架

Question

正如標題所說，即時通訊嘗試比較加蓋日期時間和加蓋日期時間。

我有一個彈性變量，它應該得到這兩個日期之間的差異值在工作日（8小時）。

「如果我在08:00郵票並加蓋了17:00，我的Flex應+1（H）」

型號：

public class FlexModel 
{ 
    public List<User> Users { get; set; } 
    public List<Stamping> Stampings { get; set; } 
    public decimal FlexTime { get; set; } 
} 

public partial class Stamping 
{ 
    [Key] 
    [DatabaseGenerated(DatabaseGeneratedOption.Identity)] 
    public int Id { get; set; } 

    [Required] 
    public int UserId { get; set; } 

    [Required] 
    [DataType(DataType.DateTime)] 
    public DateTime Timestamp { get; set; } 

    [Required] 
    [StringLength(3)] 
    public string StampingType { get; set; } 

    public virtual User User { get; set; } 
} 

查看：

@Html.LabelFor(model => model.FlexTime, htmlAttributes: new { @class = "control-label col-md-2" }) 
<div class="col-md-10"> 
    @Html.DisplayFor(model => model.FlexTime, new { htmlAttributes = new { @class = "form-control" } }) 
    @Html.ValidationMessageFor(model => model.FlexTime, "", new { @class = "text-danger" }) 
</div> 

控制器：

public ActionResult Info() 
{ 
    var flexModel = new FlexModel(); 
    var userId = (int)Session["userId"]; 
    var user = _db.Users.Find(userId); 
    var stampIn = _db.Stampings 
        .Where(i => i.StampingType == "in") 
        .Where(i => i.User == user) 
        .ToList(); 

    var stampOut = _db.Stampings 
         .Where(i => i.StampingType == "out") 
         .Where(i => i.User == user) 
         .ToList(); 

    var workDay = 8; 

    if (stampIn.Count == 0) 
    { 
     return View(); 
    } 

    foreach (var itemIn in stampIn) 
    { 
     //Dont know what to do here 
    } 

    foreach (var itemOut in stampOut) 
    { 
     //Dont know what to do here either 
    } 

    return View(); 
} 

請幫忙。

Answer 1

可以關聯列表如下：

var attendance = from sin in stampIn 
       select new 
       { 
        StampIn = sin, 
        StampOut = stampOut.FirstOrDefault(sout => 
            sout.Timestamp > sin.Timestamp) 
       }; 

這讓你STAMPIN VS stampout事件列表（雖然戳了可以爲空）。然後，你需要計算這樣的彈性工作時間：

var flexitime = from att in attendance 
       select new 
       { 
        TimeIn = att.StampIn.Timestamp, 
        TimeOut = att.StampOut == null ? (DateTime?)null : att.StampOut.Timestamp, 
        TotalTime = att.StampOut == null ? 0 : 
         att.StampOut.Timestamp.Subtract(att.StampIn.Timestamp).TotalHours 
       }; 

現在，您可以將它轉換爲您FlexModel對象（我只填寫FlexTime財產，我不知道如何/爲什麼你需要別人） ：

var workDay = 8; 
var flexModel = new FlexModel 
{ 
    FlexTime = Convert.ToDecimal(flexitime 
        .Sum(f => f.TotalTime - workDay)) 
}; 
return View(flexModel);