我想計數的時間爲前5
天的數value
出現>20
從通過柱(ncol = 1
)的數目1中所定義的特定日期。例如,日期1997.05.25
該值出現多少次>20
至1997.05.21
。計數的天數和數據範圍
下面是變量:
value <- c(37,19.75,19.5,14.5,24.75,25,25.5,19.75,19.75,14.25,21.25,21.75,17.5,16.25,14.5,
14.5,14.75,9.5,11.75,15.25,14.25,16.5,13.5,18.25,13.5,11.25,10.75,12,8.5,
9.75,14.75)
Date <- c("1997-05-01","1997-05-02","1997-05-03","1997-05-04","1997-05-05",
"1997-05-06","1997-05-07","1997-05-08","1997-05-09","1997-05-10",
"1997-05-11","1997-05-12","1997-05-13","1997-05-14","1997-05-15",
"1997-05-16","1997-05-17","1997-05-18","1997-05-19","1997-05-20",
"1997-05-21","1997-05-22","1997-05-23","1997-05-24","1997-05-25",
"1997-05-26","1997-05-27","1997-05-28","1997-05-29","1997-05-30",
"1997-05-31")
ncol <- c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)`
data <- data.frame(value, Date, ncol)
library(data.table)
setDT(data)[, ncol := ifelse(Date %in% c("1997-05-05","1997-05-11","1997-05-14",
"1997-05-18","1997-05-25"), ncol+1, 0) ]
怎麼做最好?幫助將不勝感激。
這是我期望的結果:
1. value Date ncol newcol
2. 37.00 1997-05-05 1 2
3. 19.75 1997-05-11 1 2
4. 19.50 1997-05-14 1 2
5. 14.50 1997-05-18 1 0
6. 24.75 1997-05-25 1 0
這可能是件好事,因爲要添加預期的輸出,通過答案來判斷,它是模糊的 –
感謝羅@docendo discimus。把我想得到的結果。 – Gustavo