在UITableViewCell中加載異步圖像時掛起

Question

我正在編程我的第一個iOS應用程序，我試圖將圖像異步加載到我的UITableViewCells中。我將背景中的圖像加載到NSMutableArray中，然後在cellForRowAtIndexPath方法中檢索該NSMutableArray。這些細胞能夠加載圖像，但崩潰的〜5號電池，並給了我兩個不同的錯誤之一：

SIGABRT在ApplicationCell.m的@synthesize行使用malloc：*錯誤對象0x6c30e60：雙免費

或只是進入gdb和點在iconView.image = newIcon; （線程1）。

我已經宣佈的NSMutableArray * imageArray表視圖控制器的@interface，並將其設置爲@財產，然後@ synthesize'd它：

@synthesize searchArray; 
... 
- (void)viewDidLoad { 
    [super viewDidLoad]; 
    ... 
    self.imageArray = [[NSMutableArray alloc] initWithCapacity:8]; //<-- Am I doing this correctly? 
    for (int i=0; i < 8; i++) { 
     [self.imageArray addObject:[UIImage imageNamed:@"empty.png"]]; 
    } 
    ... 
} 

將會有一個最大的8在後臺加載的圖像，這將在置於其內imageArray：

- (void)requestFinishedImage:(ASIFormDataRequest*)request { 
    //image request 
    NSData *responseData = [request responseData]; 
    NSIndexPath *index = [NSIndexPath indexPathForRow:request.tag inSection:0]; 
    UIImage *image = [[UIImage alloc] initWithData:responseData]; 
    NSLog(@"requested Image with tag: %d",request.tag); 
    [imageArray replaceObjectAtIndex:request.tag withObject:image]; 
    ApplicationCell *cell = (ApplicationCell *)[self.tableView cellForRowAtIndexPath:index]; 
    [cell setIcon2:image]; 
    cell.icon = image; 
    [image release]; 
} 

這裏是的cellForRowAtIndexPath：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { 

    static NSString *CellIdentifier = @"Cell"; 

    ApplicationCell *cell = (ApplicationCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentifier]; 
    if (cell == nil) { 
     [self.cellNib instantiateWithOwner:self options:nil]; 
     cell = tmpCell; 
     self.tmpCell = nil; 
    } 
    UIImage *image; 
    NSUInteger row = [indexPath row]; 

    [cell setItem2: [[searchArray objectAtIndex:row] objectForKey:@"item"]]; 
    [cell setPrice2: cell.price]; 
    image = [imageArray objectAtIndex:row]; 
    NSLog(@"num elements in imageArray = %d, loading: %d",[imageArray count], row); 
    [cell setIcon2: image]; 
[image release]; 
    return cell; 
} 

這裏是我的ApplicationCell.h和ApplicationCell.m

#import <Foundation/Foundation.h> 
#import <UIKit/UIKit.h> 

@interface ApplicationCell : UITableViewCell 
{ 

    UIImage *icon; 
    NSString *item; 
    NSString *price; 
    IBOutlet UIImageView *iconView; 
    IBOutlet UILabel *itemLabel; 
    IBOutlet UILabel *priceLabel; 
} 
- (void)setIcon2:(UIImage *)newIcon; 
- (void)setItem2:(NSString *)newItem; 
- (void)setPrice2:(NSString *)newPrice; 

@property(retain) UIImage *icon; 
@property(retain) NSString *item; 
@property(retain) NSString *price; 

@end 

ApplicationCell.m

#import "ApplicationCell.h" 

@implementation ApplicationCell 

@synthesize icon, item, price; 

- (void)setIcon2:(UIImage *)newIcon 
{ 
    [self setIcon:newIcon]; 
    iconView.opaque = YES; 
    iconView.image = newIcon; 
} 
- (void)setItem2:(NSString *)newItem 
{ 
    [self setItem:newItem]; 
    itemLabel.text = newItem; 
} 

- (void)setPrice2:(NSString *)newPrice 
{ 
    [self setPrice:newPrice]; 
    priceLabel.text = newPrice; 
} 


- (void)dealloc 
{ 
    [icon release]; 
    [item release]; 
    [price release]; 

    [iconView release]; 
    [itemLabel release]; 
    [priceLabel release]; 

    [super dealloc]; 
} 

@end 

有代碼可能是一些錯誤，因爲這是我第一次嘗試iOS應用程序，但請讓我知道，所以我可以學習！我一直被困在這個異步加載問題太長..任何幫助表示讚賞！

Answer 1

取出[image release]致電-tableView:cellForRowAtIndexPath:。你沒有保留它，所以你不需要釋放它。如果你使用Xcode的靜態分析器，它應該會發現像這樣的內存錯誤。