我在Parse上有云功能。當它被調用時,它將檢索一個PFObject
,然後在該對象和用戶之間添加一個關係。這部分工作正常(看到功能的結束)。 我遇到了麻煩,其選擇PFObject
忽略那些用戶已經涉及到解析雲代碼關係查詢語法
這裏查詢是我的代碼:
Parse.Cloud.define("NextMedia", function (request, response) {
var LikeRequest = Parse.Object.extend("LikeRequest");
var query = new Parse.Query(LikeRequest);
query.equalTo("completed", false);
console.log("user: " + Parse.User.current().id);
query.notEqualTo("user", Parse.User.current());
// Also only fetch if never been sent before
// HERE SHOULD USE THE BELOW RELATIONSHIP
var innerQuery = new Parse.Query(Parse.User);
innerQuery.exists(Parse.User);
query.matchesQuery("sentTo", innerQuery);
query.ascending("createdAt");
query.first({
success: function (object) {
// Successfully retrieved the object.
console.log("Got 1 object: " + object.get('mediaId'));
// Record that the user has been sent it
var user = Parse.User.current();
var relation = object.relation("sentTo"); // RELATION ADDED HERE
relation.add(user);
object.save();
response.success(object);
},
error: function (error) {
console.log("Error: " + error.code + " " + error.message);
response.error("Error getting next mediaId");
}
});
});
我敢肯定,我只是不理解如何關係查詢語法起作用。
在你的LikeRequest類中,你有一個用戶列嗎?我不理解query.notEqualTo(「user」,Parse.User.current()); – bmurmistro
在添加關係的底部,添加了許多用戶列。 – Darren
抱歉,延遲響應。你嘗試過這樣的事情: var innerQuery = LikeRequest.relation(「sendTo」)。query(); innerQuery.exists(Parse.User); – bmurmistro