3
從XML子元素值列表我有XML如下鮮明的使用XSL
<?xml version="1.0" encoding="UTF-8"?>
<Set>
<Bundles>
<BundleID>1</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>34675</TrackingID>
</BundleDetails>
<BundleQty>12</BundleQty>
</Bundles>
<Bundles>
<BundleID>2</BundleID>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>4563</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>4563</TrackingID>
</BundleDetails>
<BundleQty>34</BundleQty>
</Bundles>
<Bundles>
<BundleID>3</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>2343243</TrackingID>
</BundleDetails>
<BundleQty>22</BundleQty>
</Bundles>
<Bundles>
<BundleID>4</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>123231</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>42342</TrackingID>
</BundleDetails>
<BundleQty>33</BundleQty>
</Bundles>
<Bundles>
<BundleID>5</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>123231</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>42342</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>124512</TrackingID>
</BundleDetails>
<BundleQty>21</BundleQty>
</Bundles>
</Set>
我需要爲每套/捆綁的細節如下
Bundle# Qty Classes
1 12 A
2 34 A,B
3 22 A
4 33 A,B
5 21 A,B
我開始如下,但打擊得到不同的班級名單。需要一些指導,
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<p>Set Details</p>
<table>
<xsl:for-each select="Set/Bundles">
<tr>
<td><xsl:value-of select="BundleID"/></td>
<td><xsl:value-of select="BundleQty"/></td>
<td>--Distinct List of ./BundleDetails/Classification </td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
提前感謝您的幫助!
謝謝!
+1我要添加的唯一東西就是'Classification'的'xsl:apply-templates'的'xsl:sort'。 –
@DevNull,謝謝,你說得對。由於'Bundles'看起來已經被BundleID排序了,所以我不打算添加任何排序。我們甚至可以假設可能有多個具有相同「BundleID」的Bundles,然後我們應該添加另一個級別的分組,但這離真正的XML文檔太遠了。 –
@DimitreNovatchev謝謝! – Sr7