ORA-01791-鮮明和

Question

我想獲得不同"SkillCategory"和排序id

這裏順序是下面的腳本：

SELECT distinct EC.SKILL_CATEGORY from ETOPS_CHECK_FORM E 
INNER JOIN EC_FORM_SKILL EC 
ON EC.EC_FORM_ID=E.ID group by EC.SKILL_CATEGORY ORDER BY EC.ID 

什麼，我做錯了什麼？

Answer 1

的問題是，你需要決定其中 id排序。取出distinct，然後用在order by聚合函數：

SELECT EC.SKILL_CATEGORY 
FROM ETOPS_CHECK_FORM E INNER JOIN 
    EC_FORM_SKILL EC 
    ON EC.EC_FORM_ID = E.ID 
GROUP BY EC.SKILL_CATEGORY 
ORDER BY MIN(EC.ID); 

Answer 2

如果你只是想不使用聚合函數不重複的記錄，然後使用DISTINCT關鍵字來代替GROUP BY

試試這個：

SELECT DISTINCT EC.SKILL_CATEGORY 
FROM ETOPS_CHECK_FORM E 
INNER JOIN EC_FORM_SKILL EC ON EC.EC_FORM_ID = E.ID 
ORDER BY EC.ID; 

Answer 3

SELECT distinct EC.SKILL_CATEGORY 
FROM ETOPS_CHECK_FORM E 
    INNER JOIN EC_FORM_SKILL EC 
      ON EC.EC_FORM_ID=E.ID 
GROUP BY EC.SKILL_CATEGORY ASC 
ORDER BY MAX(EC.ID) 

Answer 4

我不知道你真正想做的...... ^^ 但是，如果你運行該腳本波紋管，你能告訴我們，如果結果是你所希望的：

Select ec.skill_category as sc 
from EC_FORM_SKILL ec 
group by sc; 

待會兒見。