爲什麼cypher在neo4j管理面板中的查詢速度比在Rails應用程序中快？

Question

這裏是我的查詢：

MATCH (me:User{username: 'username'})-[:user_posted_post|user_share_post|post_in_gr|post_in_page]->(posts1:Post) WHERE posts1.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts1) return posts1 as posts 
     UNION 
     MATCH (me:User{username: 'username'})-[{subscribe: '1'}]-()-[:post_in_gr]-(posts3:Post)-[:user_posted_post|user_share_post]-(User{status:'active'}) WHERE posts3.access IN ['everybody', 'friend'] AND posts3.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts3) RETURN posts3 as posts 
     UNION 
     MATCH (me:User{username: 'username'})-[{subscribe: '1'}]-()-[:post_in_page]-(posts4:Post)-[:user_posted_post|user_share_post]-({status:'active'}) WHERE posts4.access IN ['everybody', 'friend'] AND posts4.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts4) RETURN posts4 as posts 
     UNION 
     MATCH (me:User{username: 'username'})-[:user_author_page]-()-[:post_in_page]-(posts5:Post)-[:user_posted_post|user_share_post]-({status:'active'}) WHERE posts5.access IN ['everybody', 'friend'] AND posts5.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts5) RETURN posts5 as posts 
     UNION 
     MATCH (me:User{username: 'username'})-[{subscribe: '1'}]-({status:'active'})-[:user_posted_post|user_share_post]-(posts6:Post{system_type: 'page'}) WHERE posts6.access IN ['everybody', 'friend'] AND posts6.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts6) RETURN posts6 as posts 
     UNION 
     MATCH (me:User{username: 'username'})-[{subscribe: '1'}]-({status:'active'})-[:user_posted_post|user_share_post]-(posts7:Post) WHERE posts7.access IN ['everybody', 'friend'] AND NOT (posts7)-[:post_in_gr]-() AND NOT (posts7)-[:post_in_page]-() AND posts7.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts7) RETURN posts7 as posts 
     UNION 
     MATCH (me:User{username: 'username'})-[:user_create_com]-()-[:com_in_post]-(posts8:Post) WHERE posts8.access IN ['everybody', 'friend'] AND posts8.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts8) RETURN posts8 as posts 
     UNION 
     MATCH (me:User{username: 'username'})-[:user_can_see_post|user_posted_post]-(posts9:Post) WHERE posts9.access = 'custom' AND posts9.hidden_id IS NULL AND NOT (me)-[:user_hide_post]-(posts9) RETURN posts9 as posts").to_a 

此查詢需要在管理面板約1300毫秒，但在Rails應用程序相同的查詢需要超過4000毫秒。

在rails應用程序中，我使用Neo4j :: Session.query來進行此查詢。

Answer 1

我使用Python和Java相比，也有類似的問題。不幸的是，我無法專門與Rails集成，但是，我可以提供一些關於性能的想法：

1）檢查查詢的配置文件。請記住，你實際上是在執行8個唯一查詢 2）來看看有多重關係的查詢和未標記節點

例如：

MATCH（我：用戶{用戶名：「用戶名」}） - [：user_author_page] - （） - [：post_in_page] - （posts5：Post） - [：user_posted_post | user_share_post] - （{status：'active'}）WHERE posts5.access IN ['everybody'，'friend'] AND posts5.hidden_​​id IS NULL AND NOT（me） - [：user_hide_post] - （posts5）RETURN posts5 as posts

3）使用另一個驅動程序嘗試使用另一種語言的相同查詢。也許它的Ruby驅動程序很臭？與Java相比，python節點花費30-40倍的時間將節點轉換爲本地python對象。

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