保留在Python STR級聯元件列出轉換

Question

，我想知道如果有，讓我採取列表元素（["3D"]）和一個特定的方法，使用一個for循環中，另一個列表中嵌套它（[["3D"]]），而避免了我在[["3","D"]]中產生的當前類型轉換問題。

爲了清楚起見，我添加了以下內容：

hand = ["3D", "4D", "4C", "5D", "JS", "JC"] 

from itertools import groupby 

def generate_plays(hand): 
    plays = [] 
    for rank,suit in groupby(hand, lambda f: f[0]): 
     plays.append(list(suit)) 
    for card in hand: 
     if card not in plays:  #redundant due to list nesting 
      plays.append(list(card))  #problematic code in question 
    return plays 

輸出：

[['3D'], ['4D', '4C'], ['5D'], ['JS', 'JC'], ['3', 'D'], ['4', 'D'], ['4', 'C'], ['5', 'D'], ['J', 'S'], ['J', 'C']] 

預期輸出：

[['3D'], ['4D', '4C'], ['5D'], ['JS', 'JC'], ['4D'], ['4C'], ['5D'], ['JS'], ['JC']] 

只是重申一下，這裏的目的是保護卡元件的串聯岬在for循環。

非常感謝。

P.S.對於那些有興趣的玩家來說，它是一款紙牌遊戲的遊戲發生器，其中可以播放單張卡片和2+號碼。

Answer 1

hand = ["3D", "4D", "4C", "5D", "JS", "JC"] 

from itertools import groupby 

def generate_plays(hand): 
    plays = [] 
    for rank,suit in groupby(hand, lambda f: f[0]): 
     plays.append(list(suit)) 
    for card in hand: 
     if [card] not in plays:  #redundant due to list nesting 
      plays.append([card])  #problematic code in question 
    return plays 

print generate_plays(hand)