我正在研究IPv6,需要從頭創建一個IPv6數據包並將其放入緩衝區。不幸的是,我沒有與C多的經驗從一個教程,我已經成功地做到與IPv4的同樣的事情通過定義IPv6原始套接字編程與本地C
struct ipheader {
unsigned char iph_ihl:5, /* Little-endian */
iph_ver:4;
unsigned char iph_tos;
unsigned short int iph_len;
unsigned short int iph_ident;
unsigned char iph_flags;
unsigned short int iph_offset;
unsigned char iph_ttl;
unsigned char iph_protocol;
unsigned short int iph_chksum;
unsigned int iph_sourceip;
unsigned int iph_destip;
};
/* Structure of a TCP header */
struct tcpheader {
unsigned short int tcph_srcport;
unsigned short int tcph_destport;
unsigned int tcph_seqnum;
unsigned int tcph_acknum;
unsigned char tcph_reserved:4, tcph_offset:4;
// unsigned char tcph_flags;
unsigned int
tcp_res1:4, /*little-endian*/
tcph_hlen:4, /*length of tcp header in 32-bit words*/
tcph_fin:1, /*Finish flag "fin"*/
tcph_syn:1, /*Synchronize sequence numbers to start a connection*/
tcph_rst:1, /*Reset flag */
tcph_psh:1, /*Push, sends data to the application*/
tcph_ack:1, /*acknowledge*/
tcph_urg:1, /*urgent pointer*/
tcph_res2:2;
unsigned short int tcph_win;
unsigned short int tcph_chksum;
unsigned short int tcph_urgptr;
};
,並填補了包內容是這樣的:
// IP structure
ip->iph_ihl = 5;
ip->iph_ver = 6;
ip->iph_tos = 16;
ip->iph_len = sizeof (struct ipheader) + sizeof (struct tcpheader);
ip->iph_ident = htons(54321);
ip->iph_offset = 0;
ip->iph_ttl = 64;
ip->iph_protocol = 6; // TCP
ip->iph_chksum = 0; // Done by kernel
// Source IP, modify as needed, spoofed, we accept through command line argument
ip->iph_sourceip = inet_addr("1922.168.1.128");
// Destination IP, modify as needed, but here we accept through command line argument
ip->iph_destip = inet_addr(1922.168.1.1);
// The TCP structure. The source port, spoofed, we accept through the command line
tcp->tcph_srcport = htons(atoi("1024"));
// The destination port, we accept through command line
tcp->tcph_destport = htons(atoi("4201"));
tcp->tcph_seqnum = htons(1);
tcp->tcph_acknum = 0;
tcp->tcph_offset = 5;
tcp->tcph_syn = 1;
tcp->tcph_ack = 0;
tcp->tcph_win = htons(32767);
tcp->tcph_chksum = 0; // Done by kernel
tcp->tcph_urgptr = 0;
// IP checksum calculation
ip->iph_chksum = csum((unsigned short *) buffer, (sizeof (struct ipheader) + sizeof (struct tcpheader)));
但是對於IPv6我還沒有找到類似的方法。我已經發現是IETF這個結構,
struct ip6_hdr {
union {
struct ip6_hdrctl {
uint32_t ip6_un1_flow; /* 4 bits version, 8 bits TC, 20 bits
flow-ID */
uint16_t ip6_un1_plen; /* payload length */
uint8_t ip6_un1_nxt; /* next header */
uint8_t ip6_un1_hlim; /* hop limit */
} ip6_un1;
uint8_t ip6_un2_vfc; /* 4 bits version, top 4 bits
tclass */
} ip6_ctlun;
struct in6_addr ip6_src; /* source address */
struct in6_addr ip6_dst; /* destination address */
};
但我不知道如何填寫的信息,例如,如何從2001年發送一個TCP/SYN:220:806:22:AACC: ff:fe00:1端口1024到2001:220:806:21 :: 4端口1025?
任何人都可以幫助我或有任何參考嗎?
謝謝你,那麼多。
這是我迄今爲止所做的,但是代碼與Wireshark捕獲的真實數據包之間存在不匹配(如下面的評論所述)。我不確定可以在評論部分發佈一個長代碼,所以我只是編輯我的問題。
任何人都可以幫忙嗎?
#define PCKT_LEN 2000
int main(void) {
unsigned char buffer[PCKT_LEN];
int s;
struct sockaddr_in6 din;
struct ipv6_header *ip = (struct ipv6_header *) buffer;
struct tcpheader *tcp = (struct tcpheader *) (buffer + sizeof (struct ipv6_header));
memset(buffer, 0, PCKT_LEN);
din.sin6_family = AF_INET6;
din.sin6_port = htons(0);
inet_pton(AF_INET6, "::1", &(din.sin6_addr)); // For routing
ip->version = 6;
ip->traffic_class = 0;
ip->flow_label = 0;
ip->length = 40;
ip->next_header = 6;
ip->hop_limit = 64;
inet_pton(AF_INET6, "::1", &(ip->dst)); // IPv6
inet_pton(AF_INET6, "::1", &(ip->src)); // IPv6
tcp->tcph_srcport = htons(atoi("11111"));
tcp->tcph_destport = htons(atoi("13"));
tcp->tcph_seqnum = htons(0);
tcp->tcph_acknum = 0;
tcp->tcph_offset = 5;
tcp->tcph_syn = 1;
tcp->tcph_ack = 0;
tcp->tcph_win = htons(32752);
tcp->tcph_chksum = 0; // Done by kernel
tcp->tcph_urgptr = 0;
s = socket(PF_INET6, SOCK_RAW, IPPROTO_RAW);
if (s < 0) {
perror("socket()");
return 1;
}
unsigned short int packet_len = sizeof (struct ipv6_header) + sizeof (struct tcpheader);
if (sendto(s, buffer, packet_len, 0, (struct sockaddr*) &din, sizeof (din)) == -1) {
perror("sendto()");
close(s);
return 1;
}
close(s);
return 0;
}
是的我知道IPv6是什麼,但如何實現是在C語言是很難對我,因爲我不熟悉。例如,IPv4的結構非常簡單,我可以輕鬆理解並填寫信息。但對於IPv6來說,情況完全不同。 – nhong
@nhong:更新了答案一下。 –
謝謝你的回答,這與我從IETF獲得的結構有點不同,但無論如何,我會試一試,請耐心等待:) – nhong