2015-08-24 115 views
1

我發現我以前的代碼(從我前面的問題)是做什麼,我想,現在我有一個快速運行的代碼太慢。我添加了一個簡單的代碼來計數。至於不能重新聲明類,我看了其中涉及指像require_once(something.php)以.php文件的其他問題,我沒有這以外的任何其他文件。我試圖設置兩個文件,所以我有一個.php文件,但後來我得到了多個錯誤。這是我的代碼。PHP不能重新聲明

<?php 
error_reporting(E_ALL); 
ini_set("display_errors", 1); 
ini_set("log_errors", 0); 

$numbers = 0; 
$amout = 0; 

while ($numbers < 50) { 
    $numbers + 1; 

// This till end of class is to get the divisor numbers 
class Divisors { 
    public $factor = array(); 

    public function __construct($num) { 
    $this->num = $num; 
    } 

    // count number of divisors of a number 
    public function countDivisors() { 
    if ($this->num == 1) return 1; 

    $this->_primefactors(); 

    $array_primes = array_count_values($this->factor); 
    $divisors = 1; 
    foreach($array_primes as $power) { 
     $divisors *= ++$power; 
    } 
    return $divisors; 
    } 

    // prime factors decomposer 
    private function _primefactors() { 
    $this->factor = array(); 
    $run = true; 
    while($run && @$this->factor[0] != $this->num) { 
     $run = $this->_getFactors(); 
    } 
    } 

    // get all factors of the number 
    private function _getFactors() { 
    if($this->num == 1) { 
     return ; 
    } 
    $root = ceil(sqrt($this->num)) + 1; 
    $i = 2; 
    while($i <= $root) { 
     if($this->num % $i == 0) { 
     $this->factor[] = $i; 
     $this->num = $this->num/$i; 
     return true; 
     } 
     $i++; 
    } 
    $this->factor[] = $this->num; 
    return false; 
    } 
} // our class ends here 

$example = new Divisors($numbers); 
// Here it will check if the divisor has 5 divisors 
if ($example->countDivisors() == 5) { 
    // if true it will add 1 to the amount of numbers with 5 divisors 
    $amount + 1; 
} 
} 
// when the loop has checked 50 numbers it will print the amount 
if ($numbers == 50){ 
    print "There are $amount numbers with 5 divisors"; 
} 
?> 

我該如何解決這個問題? (其次是不是類的代碼有效嗎?)

+3

你的類是'while'循環中,因此通過循環每次重新聲明。把它移出來。 – AbraCadaver

+0

使用一些簡單的代碼縮進會很快凸顯這個 – RiggsFolly

+0

當移動出來,我得到;語法錯誤,意外'while'(T_WHILE),期望函數(T_FUNCTION) – VinceD

回答

1

您的類在while循環中聲明,並且它在每次迭代中都重新聲明。

你大概是什麼意思,是想讓它每次迭代一個新的實例。

這是修改後的代碼

<?php 
error_reporting(E_ALL); 
ini_set("display_errors", 1); 
ini_set("log_errors", 0); 

// This till end of class is to get the divisor numbers 
class Divisors 
{ 
    public $factor = array(); 

    public function __construct($num) { 
    $this->num = $num; 
    } 

    // count number of divisors of a number 
    public function countDivisors() { 
    if ($this->num == 1) return 1; 

    $this->_primefactors(); 

    $array_primes = array_count_values($this->factor); 
    $divisors = 1; 
    foreach($array_primes as $power) { 
     $divisors *= ++$power; 
    } 
    return $divisors; 
    } 

    // prime factors decomposer 
    private function _primefactors() { 
    $this->factor = array(); 
    $run = true; 
    while($run && @$this->factor[0] != $this->num) { 
     $run = $this->_getFactors(); 
    } 
    } 

    // get all factors of the number 
    private function _getFactors() { 
    if($this->num == 1) { 
     return ; 
    } 
    $root = ceil(sqrt($this->num)) + 1; 
    $i = 2; 
    while($i <= $root) { 
     if($this->num % $i == 0) { 
     $this->factor[] = $i; 
     $this->num = $this->num/$i; 
     return true; 
     } 
     $i++; 
    } 
    $this->factor[] = $this->num; 
    return false; 
    } 
} // our class ends here 

$numbers = 0; 
$amout = 0; 

while ($numbers < 50) 
{ 
    $numbers + 1; 

    $example = new Divisors($numbers); 
    // Here it will check if the divisor has 5 divisors 
    if ($example->countDivisors() == 5) { 
     // if true it will add 1 to the amount of numbers with 5 divisors 
     $amount + 1; 
    } 
} 
// when the loop has checked 50 numbers it will print the amount 
if ($numbers == 50){ 
    print "There are $amount numbers with 5 divisors"; 
} 
?> 
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