C＃與Java代碼

Question

我有一個小小的一段代碼，我在C＃中給定：

protected void Page_Load(object sender, EventArgs e) 
    { 
     try{ 
     string sFind = Request.QueryString["F"]; 
     string sFindBy = Request.QueryString["FB"]; 

     Response.ContentType = "text/xml"; 
     //Simulate Resonse (throw exeption on error) --------------------------------> 

     XmlDocument docRet = new XmlDocument(); 
     XmlElement docElement = (XmlElement)docRet.AppendChild(docRet.CreateElement("Request")); 
     generateResponseParamss(docElement, "Language", "heb"); 
     generateResponseParamss(docElement, "IMTSI", "972.001.000000081"); 
     generateResponseParamss(docElement, "Mobile", "0544490540"); 
     generateResponseParamss(docElement, "Email", "gadi.email@gmail.com"); 
     generateResponseParamss(docElement, "FirstName", "גדי"); 
     generateResponseParamss(docElement, "LastName", "גדיגדי"); 

     docRet.Save(Response.OutputStream); 

     }catch(Exception ex){ 
      ShowErrorAsXml(Response, ex); 
     } 
    } 

    public void generateResponseParamss(XmlElement docElement, string sParamsName, string sParamsValue) 
    { 
     XmlElement newNode = (XmlElement)docElement.AppendChild(docElement.OwnerDocument.CreateElement("Param")); 
     newNode.SetAttribute("Name", sParamsName); 
     newNode.SetAttribute("Value", sParamsValue); 
    } 

，我想談談這個代碼的Java，我想我需要創建一個通過接收參數的servlet URL行（「GET」），但C＃代碼行我最難治用是：

docRet.Save(Response.OutputStream); 

哪個命令做同樣在Java中。

Answer 1

Look at this tutorial.搜索StreamResult result = new StreamResult(System.out);。

更改該行有new StreamResult(new PrintStream(response.getOutputStream()));

Answer 2

有幾種方法可以做到這一點。你用什麼類來存儲xml響應？