3
我創建下面的函數dbms_lob.append錯誤還是我做錯了
function lob_replace(p_lob in out clob,p_what in varchar2,p_with in clob) return clob
as
l_temp_number number;
l_temp_number_1 number;
l_temp_clob clob;
l_return_clob clob;
l_temp1_clob clob;
l_temp2_clob clob;
begin
l_temp_number:=dbms_lob.instr(p_lob, p_what);
--Create a lob locator
DBMS_LOB.createtemporary(l_temp_clob,true);
DBMS_LOB.createtemporary(l_temp1_clob,true);
DBMS_LOB.createtemporary(l_temp2_clob,true);
---substract and build the LOBs
l_temp_number_1:=length(p_lob);
l_temp_clob:=dbms_lob.substr(p_lob,l_temp_number-1,1);
l_temp1_clob:=dbms_lob.substr(p_lob,l_temp_number_1-l_temp_number+1 ,l_temp_number +length(p_what));
--append three diff lob to one
dbms_lob.append(l_temp2_clob,l_temp_clob);
dbms_lob.append(l_temp2_clob,p_with);
dbms_lob.append(l_temp2_clob,l_temp1_clob);
l_return_clob :=l_temp2_clob;
--remove the tmp lob
DBMS_LOB.freetemporary(l_temp_clob);
DBMS_LOB.freetemporary(l_temp1_clob);
DBMS_LOB.freetemporary(l_temp2_clob);
return l_return_clob;
end;
如果我調用該函數如下
declare
temp clob;
begin
temp:='replace this #a#';
temp:=lob_replace(temp,'#a#','with this');
end;
這將拋出錯誤它會拋出以下錯誤
ORA-06502: PL/SQL: numeric or value error: invalid LOB locator specified: ORA-22275
ORA-06512: at "SYS.DBMS_LOB", line 639
ORA-06512: at "LOB_REPLACE", line 24
ORA-06512: at line 5
但是這個wi會不會引發錯誤
declare
temp clob;
begin
temp:='replace this #a# ';
temp:=lob_replace(temp,'#a#','with this');
end;
請注意最後的temp:='replace this #a# ';
額外的空間是否有任何人知道這樣做的原因?