我不確定我完全明白你想要做什麼。你的例子看起來像是一個已定義的邊界框,但是你希望它像第一個例子那樣圓形?
cartopy文檔有http://scitools.org.uk/cartopy/docs/latest/examples/always_circular_stereo.html的例子:
import matplotlib.path as mpath
import matplotlib.pyplot as plt
import numpy as np
import cartopy.crs as ccrs
import cartopy.feature
def main():
fig = plt.figure(figsize=[10, 5])
ax1 = plt.subplot(1, 2, 1, projection=ccrs.SouthPolarStereo())
ax2 = plt.subplot(1, 2, 2, projection=ccrs.SouthPolarStereo(),
sharex=ax1, sharey=ax1)
fig.subplots_adjust(bottom=0.05, top=0.95,
left=0.04, right=0.95, wspace=0.02)
# Limit the map to -60 degrees latitude and below.
ax1.set_extent([-180, 180, -90, -60], ccrs.PlateCarree())
ax1.add_feature(cartopy.feature.LAND)
ax1.add_feature(cartopy.feature.OCEAN)
ax1.gridlines()
ax2.gridlines()
ax2.add_feature(cartopy.feature.LAND)
ax2.add_feature(cartopy.feature.OCEAN)
# Compute a circle in axes coordinates, which we can use as a boundary
# for the map. We can pan/zoom as much as we like - the boundary will be
# permanently circular.
theta = np.linspace(0, 2*np.pi, 100)
center, radius = [0.5, 0.5], 0.5
verts = np.vstack([np.sin(theta), np.cos(theta)]).T
circle = mpath.Path(verts * radius + center)
ax2.set_boundary(circle, transform=ax2.transAxes)
plt.show()
if __name__ == '__main__':
main()
感謝馬特,事實上,我一直在尋找一種方式來產生圓潤的曲線,但約束邊界座標(在這種情況下,緯度)。你提供的例子正在解決這個問題。儘管如此,這並不適用於插入'ax2.stock_img()',但這沒有什麼大不了的。 –