使用PHP獲取URL的一部分

Question

我有一個網站，我需要使用PHP獲取一個網頁的URL。網址可能是東西www.mydomain.com/thestringineed/，也可以www.mydomain.com/thestringineed?data=1也可以是www.mydomain.com/ss/thestringineed

所以它總是最後一個字符串，但我不想以後得到什麼？

Answer 1

收到您將使用parse_url功能，再看看返回的路徑部分。 這樣的：

$url='www.mydomain.com/thestringineed?data=1'; 
$components=parse_url($url); 

//$mystring= end(explode('/',$components['path'])); 

// I realized after this answer had sat here for about 3 years that there was 
//a mistake in the above line 
// It would only give the last directory, so if there were extra directories in the path, it would fail. Here's the solution: 
$mystring=str_replace(reset(explode('/',$components['path'])),'',$components['path']); //This is to remove the domain from the beginning of the path. 

// In my testing, I found that if the scheme (http://, https://, ...) is present, the path does not include 
//the domain. (it's available on it's own as ['host']) In that case it's just 
// $mystring=$components['path']); 

Answer 2

parse_url應該會幫助你。

<?php 
    $url = "http://www.mydomain.com/thestringineed/"; 
    $parts = parse_url($url); 

    print_r($parts); 
?> 

Answer 3

parse_url()是您正在查找的功能。你想確切的部分，可以通過PHP_URL_PATH

$url = 'http://php.net/manual/en/function.parse-url.php'; 
echo parse_url($url, PHP_URL_PATH); 

Answer 4

使用$_SERVER['REQUEST_URI']將返回完整當前頁面的URL，你可以用「/」分開，並利用最後的數組索引。這將是最後一個字符串

Answer 5

您可以使用：

$strings = explode("/", $urlstring); 

將在URL中刪除所有的「/」並返回一個包含所有單詞的數組。

$strings[count($strings)-1] 

現在有你需要的字符串值，但它可能包含，所以我們需要刪除「數據= 1？」：

$strings2 = explode("?", $strings[count($strings)-1]); 

$strings2[0] 

擁有你是想出來的字符串網址。

希望這有助於！

Answer 6

<?php 
$url = 'http://username:password@hostname/path?arg=value#anchor'; 

print_r(parse_url($url)); 

echo parse_url($url, PHP_URL_PATH); 
?> 

和你出來說就是

Array 
(
    [scheme] => http 
    [host] => hostname 
    [user] => username 
    [pass] => password 
    [path] => /path 
    [query] => arg=value 
    [fragment] => anchor 
) 
/path