hibernate，mysql，glassfish v3和JTA數據源

Question

我正在嘗試在mysql和glassfish中使用hibernate實體管理器。我得到嘗試使用JTA數據源時，出現以下錯誤：

Caused by: org.hibernate.HibernateException: The chosen transaction strategy requires access to the JTA TransactionManager 
     at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:376) 
     at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1367) 
     at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:858) 
     at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:733) 
     ... 37 more 

這裏是如何我已經配置我的persistence.xml

<?xml version="1.0" encoding="UTF-8"?> 
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> 
    <persistence-unit name="myPU" transaction-type="JTA"> 
    <provider>org.hibernate.ejb.HibernatePersistence</provider> 
    <jta-data-source>jdbc/mysql</jta-data-source> 
    <class>com.my.shared.entity.MyFile</class> 
    <class>com.my.shared.entity.MyRole</class> 
    <class>com.my.shared.entity.MyUser</class> 
    <exclude-unlisted-classes>true</exclude-unlisted-classes> 
    <properties> 
     <property name="hibernate.hbm2ddl.auto" value="create-drop"/> 
     <property name="hibernate.show.sql" value="true" /> 
    </properties> 

然而，當我配置非jta datasource，它工作正常

<?xml version="1.0" encoding="UTF-8"?> 
    <persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> 
     <persistence-unit name="myPU" transaction-type="JTA"> 
     <provider>org.hibernate.ejb.HibernatePersistence</provider> 
     <non-jta-data-source>jdbc/mysql</non-jta-data-source> 
     <class>com.my.shared.entity.MyFile</class> 
     <class>com.my.shared.entity.MyRole</class> 
     <class>com.my.shared.entity.MyUser</class> 
     <exclude-unlisted-classes>true</exclude-unlisted-classes> 
     <properties> 
      <property name="hibernate.hbm2ddl.auto" value="create-drop"/> 
      <property name="hibernate.show.sql" value="true" /> 
     </properties> 
</persistence-unit> 
</persistence> 

這一切都很好d不錯，但我真的想用：

em.persist(myObject); 

代替：

em.getTransaction().begin(); 
em.persist(myObject); 
em.getTransaction().commit(); 

我錯過了與Hibernate配置的東西，或者是它甚至有可能使用JTA數據源？

Answer 1

對於您的配置來說，默認情況下使用容器管理的事務。在這種情況下，您需要定義一種事務同步方式，以便通知持久層（並可以更新二級緩存）。所以，你需要定義manager_lookup_class屬性如下：

// For GlassFish: 
hibernate.transaction.manager_lookup_class=org.hibernate.transaction.SunONETransactionManagerLookup 
// For WebSpere: 
hibernate.transaction.manager_lookup_class=org.hibernate.transaction.WebSphereExtendedJTATransactionLookup 
// For JBoss: 
hibernate.transaction.manager_lookup_class=org.hibernate.transaction.JBossTransactionManagerLookup 
// For OpenEJB: 
hibernate.transaction.manager_lookup_class=org.apache.openejb.hibernate.TransactionManagerLookup 

而且你必須標記訪問數據層的「交易」的經營方式。爲此，您需要使用@javax.ejb.TransactionAttribute(REQUIRED)標記它們（有關此註釋的更多信息，請參見here）。

您還可以選擇切換到Bean管理事務。你可以這樣做：

hibernate.transaction.factory_class=org.hibernate.transaction.JTATransactionFactory

那麼這個bean負責啓動/停止交易：

org.hibernate.Session session = ...; 
org.hibernate.Transaction tx = null; 
try { 
    tx = session.beginTransaction(); 
    session.createQuery(...); // do some staff 
    tx.commit(); 
} catch (HibernateException e) 
{ 
    if (tx != null) { 
     tx.rollback(); 
    } 
}