java - 從數據庫中檢索數據並使用JcomboBox進行顯示

Question

我希望能夠從數據庫中選擇數據並使用comboBox顯示它。

我有以下代碼，但它不顯示在comboBox中的數據。我意識到有代碼缺少顯示數據和我的SQL語句不正確。我只是不確定我可以做任何建議，表示讚賞。

try { Statement st = db.con.createStatement（）; （「SELECT Name，Size，Price FROM item WHERE Name =」+ comboBox_1.getToolkit（））;

   JOptionPane.showMessageDialog(frame, "displayed"); 

       while (rs.next()) { 
        String name = rs.getString("Name"); 
        String size = rs.getString("size"); 
        String price = rs.getString("price"); 
        textArea_Name.append(name); 
        textArea_size.append(size); 
        textArea_price.append(price); 
        comboBox_1.addItem(rs.getString("Name")); 
        comboBox_1.getSelectedItem(); 

       }}    


       catch (SQLException e) { 
        System.out.println("user not added"); 
        e.printStackTrace(); 
       }    

      } 
     }); 

Answer 1

試試看本教程。它確實如此。

http://www.roseindia.net/tutorial/java/swing/comboboxwithdatabaseValues.html

Answer 2

con = DriverManager.getConnection("jdbc:mysql://:3306/database","user","password"); 
    stat = con.createStatement(); 
    ResultSet rs = stat.executeQuery("select name from student;"); 
    while(rs.next()){ 
     jComboBox1.addItem(rs.getString("name")); 
     } 
    rs.close(); 
    stat.close(); 
    con.close(); 

Answer 3

try { 
Class.forName("sun.jdbc.odbc.JdbcOdbcDriver"); 

Connection conn= DriverManager.getConnection("jdbc:odbc:driverName"); 
Statement st = conn.createStatement(); 

ResultSet r=st.executeQuery("select * from tableName"); 

while (r.next()) { 

    JComboBox.addItem(r.getString("Key_Coloumn_Name")); 
} 


    conn.close(); 
    } catch (Exception e) { 
JOptionPane.showMessageDialog(null,"Failed to Connect to Database","Error Connection", JOptionPane.WARNING_MESSAGE); 
System.exit(0); 
} 

Answer 4

 try { 
      Statement stmt = db.con.createStatement(); 
     ResultSet rs = stmt5.executeQuery("select * from tbl_your_table"); 
     while (rs.next()) { 
      String pat = rs.getString("name"); 
      jComboBox.addItem(pat); 
     } 

    } catch (Exception e) { 

     JOptionPane.showMessageDialog(null, e); 
    }