我已經嘗試了其他類似問題的帖子,但我正在處理的代碼是由第三方製作的,而且我遇到了一些小問題。我根本無法用我想要的初始值定義其中一種形式。如何進行?如何在Django上預先選擇下拉菜單?
models.py
class Livro(models.Model):
codigo = models.AutoField(primary_key=True)
nome = models.CharField("Nome", max_length=50, unique = True)
autor = models.CharField("Autor", max_length=50, unique = True)
edicao = models.CharField("Edição", max_length=30, unique = True)
disciplina = models.ForeignKey(Disciplina)
tipo = models.CharField("Tipo", max_length=20, choices = Choices.tipo)
ano = models.CharField("Ano", max_length=30, choices = Choices.ano)
situacao = models.CharField("Situação", max_length=30, choices = Choices.situacao, blank = True, null = True)
def __unicode__(self):
return self.nome
views.py
def cadastrar_livro(request):
form = LivroForm(request.POST or None)
if form.is_valid():
salvo = form.save(commit=False)
salvo.situacao = "Ativado"
salvo.save()
return HttpResponseRedirect('/principal')
return render_to_response('cadastrar_livro.html', locals(), context_instance = RequestContext(request))
和choices.py
class Choices(models.Model):
tipo = (
('1', 'Seriado'),
('2', 'Único'),
)
ano = (
('1', '1º'),
('2', '2º'),
('3', '3º'),
('4', 'Único'),
)
situacao = (
('Ativado', 'Ativado'),
('Desativado', 'Desativado'),
)
我只需要situacao預先選擇Ativado卻找不到任何解決方案。需要幫助謝謝。
我不明白你爲什麼有一個單獨的選擇類,我特別不明白爲什麼它從models.Model繼承。 –
可以爲models.CharField(...,default ='Ativado')設置默認值嗎? – jarmod
就像我說的,不是我的代碼,這些文件是超級混亂的,因爲我在飛行中學習django,它使它更難.... –