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private static final String DATABASE_CREATE = "CREATE TABLE "
+ DATABASE_TABLE_USERS + "(" + KEY_ROW_ID +
" INTEGER PRIMARY KEY AUTOINCREMENT," + KEY_NAME
+ " TEXT NOT NULL," + KEY_PASSWORD + " TEXT NOT NULL," + KEY_LOGIN_ATTEMPTS + " INTEGER NOT NULL," + KEY_ZIP + " TEXT," +
KEY_STREET + " TEXT," + KEY_EMAIL + " TEXT NOT NULL," + KEY_PHONE + " TEXT);";
我創建的on_create方法數據庫: db.execSQL(DATABASE_CREATE);爲什麼我會得到一個-1 getColumnIndex方法
我有這樣的方法:
public int getLoginAttempts(String u_name) {
String [] columns = new String [] {DB_Helper.KEY_NAME};
Cursor c = database.query(DB_Helper.DATABASE_TABLE_USERS, columns, DB_Helper.KEY_NAME + "= ?",
new String[] {u_name},
null,
null,
null);
if(!c.moveToFirst()) return -1;
int c_index = c.getColumnIndex(DB_Helper.KEY_LOGIN_ATTEMPTS);
int num = c.getInt(c_index);
c.close();
return num;
}
c_index總是等於-1。這意味着該列不存在。但它確實如此。而且應該只有一條記錄回來(因爲u_names是唯一的)。
我該如何解決這個問題?
,什麼樣的信息呢那個光標持有? – user678392 2013-02-28 06:35:37
您傳遞給query()方法的'columns'數組,它只保存這些列的信息。 – 2013-02-28 06:36:43