僅顯示滿足mongodb條件的嵌套數組中的元素？

以下是我收集moviedb：僅顯示滿足mongodb條件的嵌套數組中的元素？

"_id" : ObjectId("59b9501600fcb397d6acd5bb"), 
    "theatreid" : 2, 
"name" : "carnival cinemas", 
"location" : "kanjulmarg", 
"address" : "sec 2,kanjul, Mumbai, Maharashtra 400703", 
"shows" : [ 
     { 
       "mname" : "bareily ki barfi", 
       "timings" : [ 
         10, 
         13, 
         14, 
         16, 
         22 
       ] 
     }, 

     { 
       "mname" : "Toilet:ek prem katha", 
       "timings" : [ 
         8, 
         9, 
         14, 
         16, 
         20, 
         23 
       ] 
     } 
    ] 


    "_id" : ObjectId("59b9506500fcb397d6acd5bc"), 
    "theatreid" : 3, 
    "name" : "pheonix pvr", 
"location" : "kurla", 
"address" : "sec 26,kurla, Mumbai, Maharashtra 400701", 
"shows" : [ 
     { 
       "mname" : "shubh mangal savdhan", 
       "timings" : [ 
         9, 
         11, 
         15, 
         18, 
         20 
       ] 
     }, 
     { 
       "mname" : "Toilet:ek prem katha", 
       "timings" : [ 
         8, 
         9, 
         14, 
         16, 
         20, 
         23 
       ] 
     } 
]

我要顯示與電影定時顯示（假設它是24小時格式）大於14（下午2點）。我用以下查詢：

db.moviedb.find({"shows.timings": {$gt:14}}, {shows: {$elemMatch: {timings:{$gt: 14}}}}).pretty()

它給出以下輸出：

實際

"_id" : ObjectId("59b94fc900fcb397d6acd5ba"), 
    "shows" : [ 
      { 
        "mname" : "bareily ki barfi", 
        "timings" : [ 
          10, 
          13, 
          15, 
          17, 
          21 
        ] 
      } 
    ] 


    "_id" : ObjectId("59b9501600fcb397d6acd5bb"), 
    "shows" : [ 
      { 
        "mname" : "bareily ki barfi", 
        "timings" : [ 
          10, 
          13, 
          14, 
          16, 
          22 
        ] 
      } 
    ]

但是，因爲它是觀察到的，它顯示這些元件也沿，這是不滿足條件（如10,13）。我只想要顯示那些滿足結果的元素。我希望以下列方式輸出。

預計

"_id" : ObjectId("59b94fc900fcb397d6acd5ba"), 
    "shows" : [ 
      { 
        "mname" : "bareily ki barfi", 
        "timings" : [ 

          15, 
          17, 
          21 
        ] 
      } 
    ] 


    "_id" : ObjectId("59b9501600fcb397d6acd5bb"), 
    "shows" : [ 
      { 
        "mname" : "bareily ki barfi", 
        "timings" : [ 

          16, 
          22 
        ] 
      } 
    ]

這是我甚至使用$過濾後得到的輸出，但它工作得很好，如果我給手動輸入數組。

db.moviedb.aggregate([ {  $project: {   " shows.timings": 
{    $filter: {    input: "$shows.timings",     
as: "item", 
cond: { $gte: [ "$$item", 22 ] }    }   }  } } ]) 
"_id" : ObjectId("59b94fc900fcb397d6acd5ba"), " shows" : { "timings" : [ [ 
10, 13, 15, 17, 21 ], [ 8, 11, 14, 17, 20, 22 ] ] } } 
"_id" : ObjectId("59b9501600fcb397d6acd5bb"), " shows" : { "timings" : [ [ 
10, 13, 14, 16, 22 ], [ 8, 9, 14, 16, 20, 23 ] ] } } 
"_id" : ObjectId("59b9506500fcb397d6acd5bc"), " shows" : { "timings" : [ [ 
9, 11, 15, 18, 20 ], [ 8, 9, 14, 16, 20, 23 ] ] } }

需要做什麼？請幫忙。謝謝:)

來源

2017-09-13 radhika

看起來你可以用'$ filter'做你想要的東西 - https://docs.mongodb.com/manual/reference/operator/aggregation/filter/ –

的[查找雙可能的複製嵌套數組MongoDB]（https://stackoverflow.com/questions/29071748/find-in-double-nested-array-mongodb） – Veeram

@realseanp，我用$過濾器，仍顯示不滿足條件的值。我只是想顯示滿足條件的元素只在shows.timings數組 – radhika

嘗試下面的聚合查詢。

db.moviedb.aggregate(
    [ 
     { 
     "$addFields": { 
      "shows": { 
      "$map": { 
       "input": "$shows", 
       "as": "resultm", 
       "in": { 
       "name": "$$resultm.name", 
       "timings": { 
        "$filter": { 
        "input": "$$resultm.timings", 
        "as": "resultf", 
        "cond": { 
         "$gte": [ 
         "$$resultf", 
         14 
         ] 
        } 
        } 
       } 
       } 
      } 
      } 
     } 
     } 
    ] 
)

來源

2017-09-14 16:24:40 Veeram

是的，它的工作！非常感謝：） – radhika

僅顯示滿足mongodb條件的嵌套數組中的元素？

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