在日期之間循環並顯示每個日期的記錄

Question

select * from myTable where dates between "xxxx-xx-xx" and "yyyy-yy-yy" 

我希望每個日期的表的結果。當myTable不包含該日期的記錄時，該日期的每個字段將爲空。

Answer 1

這需要動態數據生成和從我以前的答案MySQL show count of 0 for dates with no records

這裏是你可以在你的情況做

select 
t1.dates as dates, 
t2.id 
from 
(
    select a.Date as dates 
    from (
    select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date 
    from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a 
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b 
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c 
) a 
    where a.Date BETWEEN '2014-01-01' AND '2014-01-10' 
)t1 
left join 
(
    select * from myTable 
)t2 
on t2.dates = t1.dates 

DEMO

Answer 2

$from = '2014-07-01'; 
$to = '2014-07-06'; 
$empty_row = array(
    'text' => null 
); 

$from_timestamp = strtotime($from . ' midnight'); 
$to_timestamp = strtotime($to . ' midnight'); 

$dates = range($from_timestamp, $to_timestamp, 86400); 

$rows_with_dates = array(); 

foreach($dates as $date) { 
    $date = date('Y-m-d', $date); 
    $rows_with_dates[$date] = $empty_row + array('date' => $date); 
} 

$connection = new PDO('mysql:host=' . DB_HOST . ';dbname=' . DB_NAME, DB_USER, DB_PASS); 
$statement = $connection->prepare("SELECT * FROM `stackoverflow` WHERE `date` BETWEEN '$from' AND '$to'"); 
$statement->execute(); 
$rows = $statement->fetchAll(PDO::FETCH_ASSOC); 

foreach($rows as $row){ 
    $rows_with_dates[$row['date']] = $row; 
} 

print_r($rows_with_dates);