1
我想搜索一個XDocument,其中出現SerializableClass
。當SerializableClass
具有XmlRoot屬性時,它將具有與typeof(SerializableClass).Name
不同的名稱。我怎樣才能查找這個類的XmlRoot屬性?獲取某類的XmlRoot
我想搜索一個XDocument,其中出現SerializableClass
。當SerializableClass
具有XmlRoot屬性時,它將具有與typeof(SerializableClass).Name
不同的名稱。我怎樣才能查找這個類的XmlRoot屬性?獲取某類的XmlRoot
你的意思是你想要找到用於表示XML中某個元素的類的名稱?
這是我要做的事:
/// <summary>
/// Determines and returns the name of the XmlElement that should represent instances of the given type
/// in an XML stream.
/// </summary>
/// <param name="serializedObjectType"></param>
/// <returns></returns>
[SuppressMessage ("Microsoft.Design", "CA1011:ConsiderPassingBaseTypesAsParameters")]
public static string GetRootNodeElementNameForType(Type serializedObjectType)
{
// Determine if the Type contains an XmlRoot Attribute. If so, the XmlRoot attribute should contain
// the name of the element-name for this type.
// Otherwise, the name of the type should 've been used for serializing objects of this type.
XmlRootAttribute theAttrib = Attribute.GetCustomAttribute (serializedObjectType, typeof (XmlRootAttribute)) as XmlRootAttribute;
if(theAttrib != null)
{
if(String.IsNullOrEmpty (theAttrib.ElementName) == false)
{
return theAttrib.ElementName;
}
else
{
return serializedObjectType.Name;
}
}
else
{
return serializedObjectType.Name;
}
}
==假的?暴行! :D – 2011-01-28 15:03:49