排序3個人的年齡

Question

/* to find the age of individuals according to youngest to oldest */ 

#include <stdio.h> 

int main(void){ 
    int age1, age2, age3, youngest, middle, oldest; 

    printf ("Enter the age of the first individual: "); 
    scanf ("%d", &age1); 
    printf ("Enter the age of the second individual: "); 
    scanf ("%d", &age2); 
    printf ("Enter the age of the third individual: "); 
    scanf ("%d", &age3); 

    if ((age1 == age2) && (age2 == age3)){ 
     printf("All individuals have the same age of %d", &age2); 
    } 

    else (age1 != age2) && (age1 != age3) && (age2 != age3);{ 
     youngest = age1; 

     if (age1 > age2) 
      youngest = age2; 
     if (age2 > age3) 
      youngest = age3; 

     middle = age1; 

     if (age1 > age2) 
      middle = age2; 
     if (age2 < age3) 
      middle = age2; 

     oldest = age1; 

     if (age1 < age2) 
      oldest = age2; 
     if (age2 < age3) 
      oldest = age3; 

     printf("%d is the youngest.\n", youngest); 
     printf("%d is the middle.\n", middle); 
     printf("%d is the oldest.\n", oldest); 
    } 

    return 0; 

} 

嗨我改變了我的代碼，但顯示仍然顯示一個奇怪的數字，當我輸入每個人的相同年齡。我如何做到這一點，如果每個人都有同樣的年齡，那麼只有說所有人都有相同年齡的線。請幫助我作爲它的分級任務，並且即時遇到這個問題

所有人的年齡都是63567321是最年輕的。 1是中間的。 1是最古老的。

Answer 1

三個主要問題：

1. 當平等的年齡，你是路過的指針整數整數本身printf()
2. else statment沒有一個'如果」
3. 壓痕 - 不會影響執行，但對幫助您更容易在代碼中發現問題至關重要

正確的代碼：

/* to find the age of individuals according to youngest to oldest */ 

#include <stdio.h> 

int main(void) 

{ 
    int age1, age2, age3, youngest, middle, oldest; 
    printf ("Enter the age of the first individual: "); 
    scanf ("%d", &age1); 
    printf ("Enter the age of the second individual: "); 
    scanf ("%d", &age2); 
    printf ("Enter the age of the third individual: "); 
    scanf ("%d", &age3); 

    if ((age1 == age2) && (age2 == age3)) 
    { 
    printf("All individuals have the same age of %d", age2); 
    } 

    else if ((age1 != age2) && (age1 != age3) && (age2 != age3)) 
    { 
     youngest = age1; 

     if (age1 > age2) 
     youngest = age2; 
     if (age2 > age3) 
     youngest = age3; 

     middle = age1; 

     if (age1 > age2) 
     middle = age2; 
     if (age2 < age3) 
     middle = age2; 

     oldest = age1; 

     if (age1 < age2) 
     oldest = age2; 
     if (age2 < age3) 
     oldest = age3; 

     printf("%d is the youngest.\n", youngest); 
     printf("%d is the middle.\n", middle); 
     printf("%d is the oldest.\n", oldest); 
    } 

    return 0; 

} 

- 編輯

請注意，在上述方案中，如果兩個年齡都是平等的，最古老和最年輕的年齡不打印。要解決這個問題，我會刪除else的if條件，並在打印中間值之前包含一個檢查。新別的statment：

else 
    { 
     youngest = age1; 

     if (age1 > age2) 
     youngest = age2; 
     if (age2 > age3) 
     youngest = age3; 

     middle = age1; 

     if (age1 > age2) 
     middle = age2; 
     if (age2 < age3) 
     middle = age2; 

     oldest = age1; 

     if (age1 < age2) 
     oldest = age2; 
     if (age2 < age3) 
     oldest = age3; 

     printf("%d is the youngest.\n", youngest); 

     // If two ages are equivalent, do not print middle 
     if ((age1 != age2) && (age1 != age3) && (age2 != age3)) 
      printf("%d is the middle.\n", middle); 

     printf("%d is the oldest.\n", oldest); 
    } 

免責聲明：雖然我已經給出了上述解決方案，以保持原有的代碼，我寧願在下面的方式更通用的方法：

1. 創建排序的方法整數數組：sort(int *array, int size)
2. 讀輸入年齡爲整數數組：int ages[3]
3. 傳千古的排序功能：sort(ages, 3);
從排序的陣列10個
4. 打印結果：ages[0]，ages[1]，ages[2]

這樣的代碼的方式更具可讀性和可重用..

Answer 2

你爲什麼不這樣做

if (age1>age2 && age1>age3) { 
    oldest=age1; 
    if (age2>age3) 
     middle = age2; 
     youngest=age3; 
    } else { 
     middle = age3; 
     youngest=age2; 
    } 
} else if (age2>age3) { 
    oldest=age2; 
    if (age1>age3) 
     middle = age1; 
     youngest=age3; 
    } else { 
     middle = age3; 
     youngest=age1; 
    } 
} else { 
    oldest=age3; 
    if (age2>age1) 
     middle = age2; 
     youngest=age1; 
    } else { 
     middle = age1; 
     youngest=age2; 
    } 
}