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Question

我正在製作一個管理頁面，管理員可以爲特定電影和特定劇場添加節目。管理員可以添加節目，劇院名稱和電影名稱。

這是一些代碼..

<?php 
$showdatetime=$_POST['showdatetime']; 
$movieid=$_POST['movieid']; 
$theaterid=$_POST['theaterid']; 
if(empty($showdatetime)){ 
echo "Show time is a must"; 
} 
else 
{ 
$querycinema=mysql_query("SELECT show.show_datetime, show.theater_id, show.movie_id, theater.theater_name, movie.movie_name FROM `show` 
         JOIN theater ON theater.theater_id = show.theater_id 
         JOIN movie ON movie.movie_id = show.movie_id        
         WHERE show.show_datetime='$showdatetime' AND show.theater_id='$theaterid' AND show.movie_id='$movieid' "); 
$checkcinema=mysql_num_rows($querycinema); 
if($checkcinema != 0) 
{ 
echo "Sorry, ".$showdatetime." is already been scheduled for movie".$movieid." in theater ".$theaterid."."; 
} 
else 
{ 
$insert_user=mysql_query("INSERT INTO `show` (show_datetime, movie_id, theater_id) VALUES ('$showdatetime','$movieid', '$theaterid')"); 

其工作正常，但我有

echo "Sorry, ".$showdatetime." is already been scheduled for movie".$movieid." in theater ".$theaterid."."; } 

我需要一種方法來增加影片的名字和劇院名稱問題movieid和movieid選擇cz最好顯示管理員的名字不是劇院和電影的ID。

我希望這是明確的.. 謝謝

Answer 1

你已經在你的結果從查詢設置的電影名稱，以便只閱讀：

if($checkcinema != 0) 
{ 
    $data = mysql_fetch_assoc($querycinema); 
    echo "Sorry, ".$showdatetime." is already been scheduled for movie".$data['movie_name']." in theater ".$theaterid."."; 
} 

Answer 2

只需添加值到您的陣列狀這$data['theather_name'] & $data['movie_id']