Groovy正則表達式匹配不包含

Question

我需要從下面的字符串獲得每個塊Foo。我用這個正則表達式。代碼如下。但由於正則表達式的部分($|( ..F))我只得到Foo[1]和Foo[3]。我怎樣才能得到每個Foo塊與正則表達式？

import java.util.regex.Matcher 

String test = ''' ..Foo[1]dsfsdf 
    ...........sfsdfdsfsdfsdf 
    ..............sdfffffffffsd 
    ..................sdffffffffffffffff 
    ..Foo[2]dsfsdf 
    ...........sfsdfdsfsdfsdf 
    ..............sdfffffffffsd 
    ..................sdffffffffffffffff 
    ..Foo[3]dsfsdf 
    ...........sfsdfdsfsdfsdf 
    ..............sdfffffffffsd 
    ..................sdffffffffffffffff 
    ..Foo[4]dsfsdf 
    ...........sfsdfdsfsdfsdf 
    ..............sdfffffffffsd 
    ..................sdffffffffffffffff''' 

Matcher m = test =~ /(Foo\[[0-9]{1,6}\][\s\S]*?)($|( ..F))/ 
m.find(); 
//after this m.count equals 2 and contains only Foo[1] and Foo[3], but I need 4 with all Foo's 

Answer 1

你只需要通過開(後加入?=使將其變成一個positive lookahead的($|( ..F))非消費（和逃生點，使他們能夠匹配文本點）：

(Foo\[[0-9]{1,6}\][\s\S]*?)(?=$| \.\.F) 
          ^^^^^^^^^^^^^ 

查看regex demo