我正在做一個登錄活動,我希望它顯示進度對話框時,按下登錄按鈕我宣佈,初始化,並調用它,但它不顯示。 但是當我打電話的進展中的對話框上創建它出現了進度對話框聲明,初始化和調用時不顯示
這是我下面的代碼:
public class Login extends Activity {
private EditText username, password;
private Button login;
private Button signup;
String txtUsername, txtPassword, loggedin;
private ProgressDialog mProgress;
String titleId = "Logging in";
int id;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
final DatabaseHelper db = new DatabaseHelper(this);
username = (EditText) findViewById(R.id.username);
password = (EditText) findViewById(R.id.password);
login = (Button) findViewById(R.id.login);
signup = (Button) findViewById(R.id.signup);
// Login button listener
login.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
showProgress();
// Retrieve text from the EditText
txtUsername = username.getText().toString();
txtPassword = password.getText().toString();
if (txtUsername.isEmpty() && txtPassword.isEmpty()) {
mProgress.dismiss();
Toast.makeText(getApplicationContext(),"Enter Username And Password", Toast.LENGTH_LONG);
} else {
User user = db.getUser(txtUsername, txtPassword);
id = user.getId();
if (txtUsername.equalsIgnoreCase(user.getUsername())
&& txtPassword.equals(user.getPassword())) {
mProgress.dismiss();
Intent intent = new Intent(Login.this,
AdministratorPage.class);
intent.putExtra("username", "username");
intent.putExtra("id", "id");
startActivity(intent);
Toast.makeText(
getApplicationContext(),
"Successfully Logged In as "
+ user.getUsername(), Toast.LENGTH_LONG)
.show();
finish();
} else {
mProgress.dismiss();
Toast.makeText(getApplicationContext(),
"Usename Or Password Incorrect",
Toast.LENGTH_LONG).show();
username.setText("");
password.setText("");
}
}
}
});
// Sign up button listener
signup.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
showProgress();
// Retrieve text from the EditText
txtUsername = username.getText().toString();
txtPassword = password.getText().toString();
if (txtUsername.isEmpty() && txtPassword.isEmpty()) {
mProgress.dismiss();
Toast.makeText(getApplicationContext(),
"Enter Username And Password", Toast.LENGTH_LONG);
} else {
// Inserting Contacts
Log.d("Insert: ", "Inserting ..");
db.addUser(new User(txtUsername, txtPassword, "Y"));
// Reading all contacts
Log.d("Reading: ", "Reading all contacts..");
List<User> users = db.getAllUsers();
for (User cn : users) {
String log = "Id: " + cn.getId() + " ,Name: "
+ cn.getUsername() + " ,Password: "
+ cn.getPassword();
// Writing Contacts to log
Log.d("Name: ", log);
}
mProgress.dismiss();
Intent intent = new Intent(Login.this,
AdministratorPage.class);
startActivity(intent);
Toast.makeText(getApplicationContext(),
"Successfully Logged In", Toast.LENGTH_LONG).show();
finish();
}
}
});
}
public void showProgress() {
// Initialize the Progress Dialog
mProgress = new ProgressDialog(Login.this);
mProgress.setTitle(titleId);
mProgress.setMessage("Logging In Please Wait...");
mProgress.show();
}
我不知道你在期待什麼,但在你的if/else結構,你是關閉該對話框.....所以我猜這個對話框就可以看出一些毫秒,但被駁回直接.. – Opiatefuchs
我每一個案件'正在模擬器上測試它,所以通常會顯示出來,而且我最近編寫了一個類似的活動,它使用了相同的方法來顯示進度對話框,並且它正在顯示但不是此活動 –