有沒有更好的方法來寫這個？

有沒有更好的方法來做到這一點？我覺得自己因爲太重複而做錯了事。有沒有更好的方法來寫這個？

O = viz.pick(1, viz.WORLD) 

BackSetts = ["set_b1b", "set_b2a", "set_b1a", "set_b2b"] 
LeftSetts = ["set_l1a", "set_l1b", "set_l2a", "set_l1b"] 
NormSetts = ["set_nr_a", "set_nr_b"] 
Maps = ["MapA","MapB"] 

if O.name in BackSetts: 
    for i in set(BackSetts)|set(Maps): 
     WORLD[i].alpha(abs(WORLD[i].getAlpha()-1)) 

elif O.name in LeftSetts: 
    for i in set(LeftSetts)|set(Maps): 
     WORLD[i].alpha(abs(WORLD[i].getAlpha()-1)) 

elif O.name in NormSetts: 
    for i in NormSetts: 
     WORLD[i].alpha(abs(WORLD[i].getAlpha()-1))

來源

2010-10-28 relima

你想做什麼？ – katrielalex 2010-10-28 22:35:49

這段代碼告訴我的3D引擎（類似於panda3d），當鼠標點擊一個開關對象（viz.pick）時，檢查哪些「地圖」可見（alpha）作爲我的多邊形上的紋理;它顛倒了應用紋理的透明狀態。 – relima 2010-10-28 23:11:14

瑣碎的轉變是：

O = viz.pick(1, viz.WORLD) 

BackSetts = ["set_b1b", "set_b2a", "set_b1a", "set_b2b"] 
LeftSetts = ["set_l1a", "set_l1b", "set_l2a", "set_l1b"] 
NormSetts = ["set_nr_a", "set_nr_b"] 
Maps = ["MapA","MapB"] 
anyset = [] 

if O.name in BackSetts: 
    anyset = set(BackSetts)|set(Maps) 

elif O.name in LeftSetts: 
    anyset = set(LeftSetts)|set(Maps) 

elif O.name in NormSetts: 
    anyset = NormSetts 

for i in anyset: 
    WORLD[i].alpha(abs(WORLD[i].getAlpha()-1))

這需要照顧，使得NormSetts不與地圖union'd，在你原來的代碼。

來源

2010-10-28 22:39:15 carl

有沒有更好的方法來寫這個？

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